0.33/0.49	NO
0.83/0.50	
0.83/0.50	Problem:
0.83/0.50	 a(b(a(x1))) -> b(b(b(x1)))
0.83/0.50	 b(a(b(x1))) -> a(b(a(x1)))
0.83/0.50	
0.83/0.50	Proof:
0.83/0.50	 Unfolding Processor:
0.83/0.50	  loop length: 6
0.83/0.50	  terms:
0.83/0.50	   a(b(a(a(b(b(x926))))))
0.83/0.50	   b(b(b(a(b(b(x926))))))
0.83/0.50	   b(b(a(b(a(b(x926))))))
0.83/0.50	   b(b(a(a(b(a(x926))))))
0.83/0.50	   b(b(a(b(b(b(x926))))))
0.83/0.50	   b(a(b(a(b(b(x926))))))
0.83/0.50	  context: []
0.83/0.50	  substitution:
0.83/0.50	   x926 -> x926
0.83/0.50	  Qed
0.83/0.50	EOF