0.58/0.62	NO
0.58/0.62	
0.58/0.62	Problem:
0.58/0.62	 b(a(a(x1))) -> a(x1)
0.58/0.62	 a(a(a(x1))) -> b(b(b(x1)))
0.58/0.62	 b(b(x1)) -> a(b(a(x1)))
0.58/0.62	
0.58/0.62	Proof:
0.58/0.62	 String Reversal Processor:
0.58/0.62	  a(a(b(x1))) -> a(x1)
0.58/0.62	  a(a(a(x1))) -> b(b(b(x1)))
0.58/0.62	  b(b(x1)) -> a(b(a(x1)))
0.58/0.62	  Unfolding Processor:
0.58/0.62	   loop length: 6
0.58/0.62	   terms:
0.58/0.62	    a(a(a(b(a(a(x2342))))))
0.58/0.62	    b(b(b(b(a(a(x2342))))))
0.58/0.62	    a(b(a(b(b(a(a(x2342)))))))
0.58/0.62	    a(b(a(a(b(a(a(a(x2342))))))))
0.58/0.62	    a(b(a(a(b(b(b(b(x2342))))))))
0.58/0.62	    a(b(a(a(a(b(a(b(b(x2342)))))))))
0.58/0.62	   context: a(b([]))
0.58/0.62	   substitution:
0.58/0.62	    x2342 -> b(a(x2342))
0.58/0.62	   Qed
0.58/0.63	EOF