83.80/21.60	NO
83.80/21.60	
83.80/21.60	Problem:
83.80/21.60	 a(x1) -> x1
83.80/21.60	 a(x1) -> b(x1)
83.80/21.60	 b(b(c(x1))) -> a(c(c(c(a(b(x1))))))
83.80/21.60	
83.80/21.60	Proof:
83.80/21.60	 String Reversal Processor:
83.80/21.60	  a(x1) -> x1
83.80/21.60	  a(x1) -> b(x1)
83.80/21.60	  c(b(b(x1))) -> b(a(c(c(c(a(x1))))))
83.80/21.60	  Unfolding Processor:
83.80/21.60	   loop length: 11
83.80/21.60	   terms:
83.80/21.60	    c(b(b(b(b(x161959)))))
83.80/21.60	    b(a(c(c(c(a(b(b(x161959))))))))
83.80/21.60	    b(a(c(c(c(b(b(b(x161959))))))))
83.80/21.60	    b(a(c(c(b(a(c(c(c(a(b(x161959)))))))))))
83.80/21.60	    b(a(c(c(b(b(c(c(c(a(b(x161959)))))))))))
83.80/21.60	    b(a(c(c(b(b(c(c(c(b(b(x161959)))))))))))
83.80/21.60	    b(a(c(c(b(b(c(c(b(a(c(c(c(a(x161959))))))))))))))
83.80/21.60	    b(a(c(c(b(b(c(c(b(b(c(c(c(a(x161959))))))))))))))
83.80/21.60	    b(a(c(c(b(b(c(b(a(c(c(c(a(c(c(c(a(x161959)))))))))))))))))
83.80/21.60	    b(a(c(c(b(b(c(b(b(c(c(c(a(c(c(c(a(x161959)))))))))))))))))
83.80/21.60	    b(a(c(c(b(b(b(a(c(c(c(a(c(c(c(a(c(c(c(a(x161959))))))))))))))))))))
83.80/21.60	   context: b(a(c([])))
83.80/21.60	   substitution:
83.80/21.60	    x161959 -> c(c(c(a(c(c(c(a(c(c(c(a(x161959))))))))))))
83.80/21.60	   Qed
83.80/21.60	EOF