26.39/7.74 YES 26.39/7.75 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 26.39/7.75 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 26.39/7.75 26.39/7.75 26.39/7.75 Termination w.r.t. Q of the given QTRS could be proven: 26.39/7.75 26.39/7.75 (0) QTRS 26.39/7.75 (1) DependencyPairsProof [EQUIVALENT, 20 ms] 26.39/7.75 (2) QDP 26.39/7.75 (3) DependencyGraphProof [EQUIVALENT, 1 ms] 26.39/7.75 (4) QDP 26.39/7.75 (5) QDPOrderProof [EQUIVALENT, 11 ms] 26.39/7.75 (6) QDP 26.39/7.75 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 26.39/7.75 (8) TRUE 26.39/7.75 26.39/7.75 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (0) 26.39/7.75 Obligation: 26.39/7.75 Q restricted rewrite system: 26.39/7.75 The TRS R consists of the following rules: 26.39/7.75 26.39/7.75 a(x1) -> x1 26.39/7.75 a(b(x1)) -> c(x1) 26.39/7.75 b(x1) -> x1 26.39/7.75 c(c(x1)) -> b(b(a(a(c(x1))))) 26.39/7.75 26.39/7.75 Q is empty. 26.39/7.75 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (1) DependencyPairsProof (EQUIVALENT) 26.39/7.75 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (2) 26.39/7.75 Obligation: 26.39/7.75 Q DP problem: 26.39/7.75 The TRS P consists of the following rules: 26.39/7.75 26.39/7.75 A(b(x1)) -> C(x1) 26.39/7.75 C(c(x1)) -> B(b(a(a(c(x1))))) 26.39/7.75 C(c(x1)) -> B(a(a(c(x1)))) 26.39/7.75 C(c(x1)) -> A(a(c(x1))) 26.39/7.75 C(c(x1)) -> A(c(x1)) 26.39/7.75 26.39/7.75 The TRS R consists of the following rules: 26.39/7.75 26.39/7.75 a(x1) -> x1 26.39/7.75 a(b(x1)) -> c(x1) 26.39/7.75 b(x1) -> x1 26.39/7.75 c(c(x1)) -> b(b(a(a(c(x1))))) 26.39/7.75 26.39/7.75 Q is empty. 26.39/7.75 We have to consider all minimal (P,Q,R)-chains. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (3) DependencyGraphProof (EQUIVALENT) 26.39/7.75 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (4) 26.39/7.75 Obligation: 26.39/7.75 Q DP problem: 26.39/7.75 The TRS P consists of the following rules: 26.39/7.75 26.39/7.75 C(c(x1)) -> A(a(c(x1))) 26.39/7.75 A(b(x1)) -> C(x1) 26.39/7.75 C(c(x1)) -> A(c(x1)) 26.39/7.75 26.39/7.75 The TRS R consists of the following rules: 26.39/7.75 26.39/7.75 a(x1) -> x1 26.39/7.75 a(b(x1)) -> c(x1) 26.39/7.75 b(x1) -> x1 26.39/7.75 c(c(x1)) -> b(b(a(a(c(x1))))) 26.39/7.75 26.39/7.75 Q is empty. 26.39/7.75 We have to consider all minimal (P,Q,R)-chains. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (5) QDPOrderProof (EQUIVALENT) 26.39/7.75 We use the reduction pair processor [LPAR04,JAR06]. 26.39/7.75 26.39/7.75 26.39/7.75 The following pairs can be oriented strictly and are deleted. 26.39/7.75 26.39/7.75 A(b(x1)) -> C(x1) 26.39/7.75 The remaining pairs can at least be oriented weakly. 26.39/7.75 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 26.39/7.75 26.39/7.75 <<< 26.39/7.75 POL(C(x_1)) = [[0A]] + [[-I, 0A, -I]] * x_1 26.39/7.75 >>> 26.39/7.75 26.39/7.75 <<< 26.39/7.75 POL(c(x_1)) = [[1A], [-I], [-I]] + [[0A, -I, 0A], [0A, 1A, 0A], [0A, 1A, 0A]] * x_1 26.39/7.75 >>> 26.39/7.75 26.39/7.75 <<< 26.39/7.75 POL(A(x_1)) = [[0A]] + [[-I, 0A, 0A]] * x_1 26.39/7.75 >>> 26.39/7.75 26.39/7.75 <<< 26.39/7.75 POL(a(x_1)) = [[0A], [-I], [-I]] + [[0A, 0A, 0A], [-I, 0A, 0A], [-I, 0A, 0A]] * x_1 26.39/7.75 >>> 26.39/7.75 26.39/7.75 <<< 26.39/7.75 POL(b(x_1)) = [[-I], [0A], [1A]] + [[0A, 0A, -I], [-I, 0A, -I], [0A, 1A, 0A]] * x_1 26.39/7.75 >>> 26.39/7.75 26.39/7.75 26.39/7.75 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 26.39/7.75 26.39/7.75 c(c(x1)) -> b(b(a(a(c(x1))))) 26.39/7.75 a(x1) -> x1 26.39/7.75 a(b(x1)) -> c(x1) 26.39/7.75 b(x1) -> x1 26.39/7.75 26.39/7.75 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (6) 26.39/7.75 Obligation: 26.39/7.75 Q DP problem: 26.39/7.75 The TRS P consists of the following rules: 26.39/7.75 26.39/7.75 C(c(x1)) -> A(a(c(x1))) 26.39/7.75 C(c(x1)) -> A(c(x1)) 26.39/7.75 26.39/7.75 The TRS R consists of the following rules: 26.39/7.75 26.39/7.75 a(x1) -> x1 26.39/7.75 a(b(x1)) -> c(x1) 26.39/7.75 b(x1) -> x1 26.39/7.75 c(c(x1)) -> b(b(a(a(c(x1))))) 26.39/7.75 26.39/7.75 Q is empty. 26.39/7.75 We have to consider all minimal (P,Q,R)-chains. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (7) DependencyGraphProof (EQUIVALENT) 26.39/7.75 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 2 less nodes. 26.39/7.75 ---------------------------------------- 26.39/7.75 26.39/7.75 (8) 26.39/7.75 TRUE 26.79/7.90 EOF