24.80/7.27 YES 24.80/7.28 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 24.80/7.28 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 24.80/7.28 24.80/7.28 24.80/7.28 Termination w.r.t. Q of the given QTRS could be proven: 24.80/7.28 24.80/7.28 (0) QTRS 24.80/7.28 (1) QTRS Reverse [EQUIVALENT, 0 ms] 24.80/7.28 (2) QTRS 24.80/7.28 (3) DependencyPairsProof [EQUIVALENT, 0 ms] 24.80/7.28 (4) QDP 24.80/7.28 (5) DependencyGraphProof [EQUIVALENT, 7 ms] 24.80/7.28 (6) QDP 24.80/7.28 (7) QDPOrderProof [EQUIVALENT, 133 ms] 24.80/7.28 (8) QDP 24.80/7.28 (9) QDPOrderProof [EQUIVALENT, 0 ms] 24.80/7.28 (10) QDP 24.80/7.28 (11) UsableRulesProof [EQUIVALENT, 0 ms] 24.80/7.28 (12) QDP 24.80/7.28 (13) QDPSizeChangeProof [EQUIVALENT, 0 ms] 24.80/7.28 (14) YES 24.80/7.28 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (0) 24.80/7.28 Obligation: 24.80/7.28 Q restricted rewrite system: 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> b(b(c(b(c(x1))))) 24.80/7.28 c(b(b(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (1) QTRS Reverse (EQUIVALENT) 24.80/7.28 We applied the QTRS Reverse Processor [REVERSE]. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (2) 24.80/7.28 Obligation: 24.80/7.28 Q restricted rewrite system: 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (3) DependencyPairsProof (EQUIVALENT) 24.80/7.28 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (4) 24.80/7.28 Obligation: 24.80/7.28 Q DP problem: 24.80/7.28 The TRS P consists of the following rules: 24.80/7.28 24.80/7.28 A(x1) -> C(b(c(b(b(x1))))) 24.80/7.28 A(x1) -> B(c(b(b(x1)))) 24.80/7.28 A(x1) -> C(b(b(x1))) 24.80/7.28 A(x1) -> B(b(x1)) 24.80/7.28 A(x1) -> B(x1) 24.80/7.28 B(b(c(x1))) -> A(x1) 24.80/7.28 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 We have to consider all minimal (P,Q,R)-chains. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (5) DependencyGraphProof (EQUIVALENT) 24.80/7.28 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 2 less nodes. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (6) 24.80/7.28 Obligation: 24.80/7.28 Q DP problem: 24.80/7.28 The TRS P consists of the following rules: 24.80/7.28 24.80/7.28 A(x1) -> B(c(b(b(x1)))) 24.80/7.28 B(b(c(x1))) -> A(x1) 24.80/7.28 A(x1) -> B(b(x1)) 24.80/7.28 A(x1) -> B(x1) 24.80/7.28 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 We have to consider all minimal (P,Q,R)-chains. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (7) QDPOrderProof (EQUIVALENT) 24.80/7.28 We use the reduction pair processor [LPAR04,JAR06]. 24.80/7.28 24.80/7.28 24.80/7.28 The following pairs can be oriented strictly and are deleted. 24.80/7.28 24.80/7.28 A(x1) -> B(b(x1)) 24.80/7.28 The remaining pairs can at least be oriented weakly. 24.80/7.28 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(A(x_1)) = [[1A]] + [[0A, 1A, 0A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(B(x_1)) = [[0A]] + [[0A, -I, -I]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(c(x_1)) = [[0A], [1A], [0A]] + [[-I, 0A, 0A], [0A, 1A, 1A], [-I, 0A, 0A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(b(x_1)) = [[0A], [0A], [0A]] + [[-I, 0A, -I], [0A, -I, 0A], [-I, -I, 0A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(a(x_1)) = [[0A], [1A], [0A]] + [[-I, 0A, 0A], [0A, 1A, 1A], [-I, 0A, 0A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 24.80/7.28 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 24.80/7.28 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (8) 24.80/7.28 Obligation: 24.80/7.28 Q DP problem: 24.80/7.28 The TRS P consists of the following rules: 24.80/7.28 24.80/7.28 A(x1) -> B(c(b(b(x1)))) 24.80/7.28 B(b(c(x1))) -> A(x1) 24.80/7.28 A(x1) -> B(x1) 24.80/7.28 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 We have to consider all minimal (P,Q,R)-chains. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (9) QDPOrderProof (EQUIVALENT) 24.80/7.28 We use the reduction pair processor [LPAR04,JAR06]. 24.80/7.28 24.80/7.28 24.80/7.28 The following pairs can be oriented strictly and are deleted. 24.80/7.28 24.80/7.28 A(x1) -> B(c(b(b(x1)))) 24.80/7.28 The remaining pairs can at least be oriented weakly. 24.80/7.28 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(A(x_1)) = [[1A]] + [[0A, 0A, 1A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(B(x_1)) = [[0A]] + [[0A, -I, -I]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(c(x_1)) = [[0A], [0A], [1A]] + [[-I, -I, 0A], [0A, 0A, 0A], [0A, 0A, 1A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(b(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, 0A], [0A, 0A, -I], [0A, -I, -I]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 <<< 24.80/7.28 POL(a(x_1)) = [[0A], [1A], [1A]] + [[-I, -I, 0A], [0A, 0A, 1A], [0A, 0A, 1A]] * x_1 24.80/7.28 >>> 24.80/7.28 24.80/7.28 24.80/7.28 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 24.80/7.28 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (10) 24.80/7.28 Obligation: 24.80/7.28 Q DP problem: 24.80/7.28 The TRS P consists of the following rules: 24.80/7.28 24.80/7.28 B(b(c(x1))) -> A(x1) 24.80/7.28 A(x1) -> B(x1) 24.80/7.28 24.80/7.28 The TRS R consists of the following rules: 24.80/7.28 24.80/7.28 a(x1) -> c(b(c(b(b(x1))))) 24.80/7.28 b(b(c(x1))) -> a(x1) 24.80/7.28 c(c(x1)) -> x1 24.80/7.28 24.80/7.28 Q is empty. 24.80/7.28 We have to consider all minimal (P,Q,R)-chains. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (11) UsableRulesProof (EQUIVALENT) 24.80/7.28 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (12) 24.80/7.28 Obligation: 24.80/7.28 Q DP problem: 24.80/7.28 The TRS P consists of the following rules: 24.80/7.28 24.80/7.28 B(b(c(x1))) -> A(x1) 24.80/7.28 A(x1) -> B(x1) 24.80/7.28 24.80/7.28 R is empty. 24.80/7.28 Q is empty. 24.80/7.28 We have to consider all minimal (P,Q,R)-chains. 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (13) QDPSizeChangeProof (EQUIVALENT) 24.80/7.28 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 24.80/7.28 24.80/7.28 From the DPs we obtained the following set of size-change graphs: 24.80/7.28 *A(x1) -> B(x1) 24.80/7.28 The graph contains the following edges 1 >= 1 24.80/7.28 24.80/7.28 24.80/7.28 *B(b(c(x1))) -> A(x1) 24.80/7.28 The graph contains the following edges 1 > 1 24.80/7.28 24.80/7.28 24.80/7.28 ---------------------------------------- 24.80/7.28 24.80/7.28 (14) 24.80/7.28 YES 25.17/7.35 EOF