1.24/0.70	NO
1.24/0.70	
1.24/0.70	Problem:
1.24/0.70	 a(x1) -> x1
1.24/0.70	 a(b(x1)) -> b(a(c(b(a(a(x1))))))
1.24/0.70	 c(b(c(x1))) -> x1
1.24/0.70	
1.24/0.70	Proof:
1.24/0.70	 String Reversal Processor:
1.24/0.70	  a(x1) -> x1
1.24/0.70	  b(a(x1)) -> a(a(b(c(a(b(x1))))))
1.24/0.70	  c(b(c(x1))) -> x1
1.24/0.70	  Unfolding Processor:
1.24/0.70	   loop length: 7
1.24/0.70	   terms:
1.24/0.70	    b(a(a(a(x4731))))
1.24/0.70	    a(a(b(c(a(b(a(a(x4731))))))))
1.24/0.70	    a(a(b(c(b(a(a(x4731)))))))
1.24/0.70	    a(a(b(c(a(a(b(c(a(b(a(x4731)))))))))))
1.24/0.70	    a(a(b(c(a(b(c(a(b(a(x4731))))))))))
1.24/0.70	    a(a(b(c(b(c(a(b(a(x4731)))))))))
1.24/0.70	    a(a(b(a(b(a(x4731))))))
1.24/0.70	   context: a(a([]))
1.24/0.70	   substitution:
1.24/0.70	    x4731 -> b(c(a(b(x4731))))
1.24/0.70	   Qed
1.24/0.71	EOF