6.98/2.11	NO
6.98/2.11	
6.98/2.11	Problem:
6.98/2.11	 a(x1) -> x1
6.98/2.11	 a(b(x1)) -> b(a(c(b(a(x1)))))
6.98/2.11	 b(x1) -> a(x1)
6.98/2.11	 c(c(x1)) -> x1
6.98/2.11	
6.98/2.11	Proof:
6.98/2.11	 String Reversal Processor:
6.98/2.11	  a(x1) -> x1
6.98/2.11	  b(a(x1)) -> a(b(c(a(b(x1)))))
6.98/2.11	  b(x1) -> a(x1)
6.98/2.11	  c(c(x1)) -> x1
6.98/2.11	  Unfolding Processor:
6.98/2.11	   loop length: 8
6.98/2.11	   terms:
6.98/2.11	    b(a(a(x36400)))
6.98/2.11	    a(b(c(a(b(a(x36400))))))
6.98/2.11	    a(b(c(b(a(x36400)))))
6.98/2.11	    a(b(c(a(b(c(a(b(x36400))))))))
6.98/2.11	    a(b(c(b(c(a(b(x36400)))))))
6.98/2.11	    a(b(c(a(c(a(b(x36400)))))))
6.98/2.11	    a(b(c(c(a(b(x36400))))))
6.98/2.11	    a(b(a(b(x36400))))
6.98/2.11	   context: a([])
6.98/2.11	   substitution:
6.98/2.11	    x36400 -> x36400
6.98/2.11	   Qed
6.98/2.15	EOF