19.16/5.84 YES 19.32/5.88 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 19.32/5.88 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 19.32/5.88 19.32/5.88 19.32/5.88 Termination w.r.t. Q of the given QTRS could be proven: 19.32/5.88 19.32/5.88 (0) QTRS 19.32/5.88 (1) QTRS Reverse [EQUIVALENT, 0 ms] 19.32/5.88 (2) QTRS 19.32/5.88 (3) DependencyPairsProof [EQUIVALENT, 9 ms] 19.32/5.88 (4) QDP 19.32/5.88 (5) MRRProof [EQUIVALENT, 66 ms] 19.32/5.88 (6) QDP 19.32/5.88 (7) QDPOrderProof [EQUIVALENT, 0 ms] 19.32/5.88 (8) QDP 19.32/5.88 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 19.32/5.88 (10) TRUE 19.32/5.88 19.32/5.88 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (0) 19.32/5.88 Obligation: 19.32/5.88 Q restricted rewrite system: 19.32/5.88 The TRS R consists of the following rules: 19.32/5.88 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 a(b(b(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(b(c(a(x1)))) 19.32/5.88 19.32/5.88 Q is empty. 19.32/5.88 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (1) QTRS Reverse (EQUIVALENT) 19.32/5.88 We applied the QTRS Reverse Processor [REVERSE]. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (2) 19.32/5.88 Obligation: 19.32/5.88 Q restricted rewrite system: 19.32/5.88 The TRS R consists of the following rules: 19.32/5.88 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 b(b(a(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(c(b(a(x1)))) 19.32/5.88 19.32/5.88 Q is empty. 19.32/5.88 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (3) DependencyPairsProof (EQUIVALENT) 19.32/5.88 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (4) 19.32/5.88 Obligation: 19.32/5.88 Q DP problem: 19.32/5.88 The TRS P consists of the following rules: 19.32/5.88 19.32/5.88 A(x1) -> B(x1) 19.32/5.88 B(b(a(x1))) -> C(x1) 19.32/5.88 C(c(x1)) -> A(c(b(a(x1)))) 19.32/5.88 C(c(x1)) -> C(b(a(x1))) 19.32/5.88 C(c(x1)) -> B(a(x1)) 19.32/5.88 C(c(x1)) -> A(x1) 19.32/5.88 19.32/5.88 The TRS R consists of the following rules: 19.32/5.88 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 b(b(a(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(c(b(a(x1)))) 19.32/5.88 19.32/5.88 Q is empty. 19.32/5.88 We have to consider all minimal (P,Q,R)-chains. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (5) MRRProof (EQUIVALENT) 19.32/5.88 By using the rule removal processor [LPAR04] with the following ordering, at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented. 19.32/5.88 19.32/5.88 Strictly oriented dependency pairs: 19.32/5.88 19.32/5.88 C(c(x1)) -> C(b(a(x1))) 19.32/5.88 C(c(x1)) -> B(a(x1)) 19.32/5.88 C(c(x1)) -> A(x1) 19.32/5.88 19.32/5.88 19.32/5.88 Used ordering: Polynomial interpretation [POLO]: 19.32/5.88 19.32/5.88 POL(A(x_1)) = x_1 19.32/5.88 POL(B(x_1)) = x_1 19.32/5.88 POL(C(x_1)) = 2 + x_1 19.32/5.88 POL(a(x_1)) = 1 + x_1 19.32/5.88 POL(b(x_1)) = 1 + x_1 19.32/5.88 POL(c(x_1)) = 3 + x_1 19.32/5.88 19.32/5.88 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (6) 19.32/5.88 Obligation: 19.32/5.88 Q DP problem: 19.32/5.88 The TRS P consists of the following rules: 19.32/5.88 19.32/5.88 A(x1) -> B(x1) 19.32/5.88 B(b(a(x1))) -> C(x1) 19.32/5.88 C(c(x1)) -> A(c(b(a(x1)))) 19.32/5.88 19.32/5.88 The TRS R consists of the following rules: 19.32/5.88 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 b(b(a(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(c(b(a(x1)))) 19.32/5.88 19.32/5.88 Q is empty. 19.32/5.88 We have to consider all minimal (P,Q,R)-chains. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (7) QDPOrderProof (EQUIVALENT) 19.32/5.88 We use the reduction pair processor [LPAR04,JAR06]. 19.32/5.88 19.32/5.88 19.32/5.88 The following pairs can be oriented strictly and are deleted. 19.32/5.88 19.32/5.88 B(b(a(x1))) -> C(x1) 19.32/5.88 The remaining pairs can at least be oriented weakly. 19.32/5.88 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(A(x_1)) = [[0A]] + [[-I, 0A, -I]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(B(x_1)) = [[0A]] + [[-I, 0A, -I]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(b(x_1)) = [[0A], [-I], [-I]] + [[0A, 1A, 0A], [0A, 0A, -I], [-I, 0A, -I]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(a(x_1)) = [[0A], [-I], [0A]] + [[1A, 1A, 0A], [0A, 0A, -I], [0A, 0A, -I]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(C(x_1)) = [[-I]] + [[0A, 0A, -I]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 <<< 19.32/5.88 POL(c(x_1)) = [[0A], [0A], [0A]] + [[0A, 0A, 1A], [-I, -I, 0A], [1A, 1A, 0A]] * x_1 19.32/5.88 >>> 19.32/5.88 19.32/5.88 19.32/5.88 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 19.32/5.88 19.32/5.88 b(b(a(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(c(b(a(x1)))) 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 19.32/5.88 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (8) 19.32/5.88 Obligation: 19.32/5.88 Q DP problem: 19.32/5.88 The TRS P consists of the following rules: 19.32/5.88 19.32/5.88 A(x1) -> B(x1) 19.32/5.88 C(c(x1)) -> A(c(b(a(x1)))) 19.32/5.88 19.32/5.88 The TRS R consists of the following rules: 19.32/5.88 19.32/5.88 a(x1) -> b(x1) 19.32/5.88 b(b(a(x1))) -> c(x1) 19.32/5.88 c(c(x1)) -> a(c(b(a(x1)))) 19.32/5.88 19.32/5.88 Q is empty. 19.32/5.88 We have to consider all minimal (P,Q,R)-chains. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (9) DependencyGraphProof (EQUIVALENT) 19.32/5.88 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 2 less nodes. 19.32/5.88 ---------------------------------------- 19.32/5.88 19.32/5.88 (10) 19.32/5.88 TRUE 19.56/5.97 EOF