0.00/0.49	NO
0.00/0.49	
0.00/0.49	
0.00/0.49	The system was reversed.
0.00/0.49	
0.00/0.49	Remains to prove termination of the 4-rule system
0.00/0.49	{ a -> ,
0.00/0.49	  a a a -> b ,
0.00/0.49	  c b -> b c a c ,
0.00/0.49	  c -> }
0.00/0.49	
0.00/0.49	
0.00/0.49	Loop of length 12 starting with a string of length 5 using right expansion
0.00/0.49	and the encoding {a=a, b=b, c=c}:
0.00/0.49	
0.00/0.49	.cb.bba
0.00/0.49		rule cb -> bcac at position 0
0.00/0.49	.bcac.bba
0.00/0.49		rule a ->  at position 2
0.00/0.49	.bcc.bba
0.00/0.49		rule cb -> bcac at position 2
0.00/0.49	.bcbcac.ba
0.00/0.49		rule a ->  at position 4
0.00/0.49	.bcbcc.ba
0.00/0.49		rule cb -> bcac at position 4
0.00/0.49	.bcbcbcac.a
0.00/0.49		rule cb -> bcac at position 3
0.00/0.49	.bcbbcaccac.a
0.00/0.49		rule c ->  at position 6
0.00/0.49	.bcbbcacac.a
0.00/0.49		rule c ->  at position 6
0.00/0.49	.bcbbcaac.a
0.00/0.49		rule c ->  at position 7
0.00/0.49	.bcbbcaa.a
0.00/0.49		rule aaa -> b at position 5
0.00/0.49	.bcbbcb.
0.00/0.49		rule cb -> bcac at position 4
0.00/0.49	.bcbbbcac.
0.00/0.49		rule c ->  at position 5
0.00/0.49	.bcbbbac.
1.32/0.55	EOF