1.02/0.63	NO
1.02/0.63	
1.02/0.63	Problem:
1.02/0.63	 a(x1) -> x1
1.02/0.63	 a(b(x1)) -> a(a(c(b(b(a(x1))))))
1.02/0.63	 b(x1) -> x1
1.02/0.63	 c(c(x1)) -> x1
1.02/0.63	
1.02/0.63	Proof:
1.02/0.63	 String Reversal Processor:
1.02/0.63	  a(x1) -> x1
1.02/0.63	  b(a(x1)) -> a(b(b(c(a(a(x1))))))
1.02/0.63	  b(x1) -> x1
1.02/0.63	  c(c(x1)) -> x1
1.02/0.63	  Unfolding Processor:
1.02/0.63	   loop length: 7
1.02/0.63	   terms:
1.02/0.63	    b(a(c(a(x1210))))
1.02/0.63	    a(b(b(c(a(a(c(a(x1210))))))))
1.02/0.63	    a(b(b(c(a(c(a(x1210)))))))
1.02/0.63	    a(b(b(c(c(a(x1210))))))
1.02/0.63	    a(b(b(a(x1210))))
1.02/0.63	    a(b(a(b(b(c(a(a(x1210))))))))
1.02/0.63	    a(b(a(b(c(a(a(x1210)))))))
1.02/0.63	   context: a([])
1.02/0.63	   substitution:
1.02/0.63	    x1210 -> a(x1210)
1.02/0.63	   Qed
1.02/0.64	EOF