0.34/0.65	NO
0.34/0.65	
0.34/0.65	Problem:
0.34/0.65	 a(x1) -> x1
0.34/0.65	 a(b(x1)) -> a(c(b(b(a(a(x1))))))
0.34/0.65	 b(x1) -> x1
0.34/0.65	 c(c(x1)) -> x1
0.34/0.65	
0.34/0.65	Proof:
0.34/0.65	 String Reversal Processor:
0.34/0.65	  a(x1) -> x1
0.34/0.65	  b(a(x1)) -> a(a(b(b(c(a(x1))))))
0.34/0.65	  b(x1) -> x1
0.34/0.65	  c(c(x1)) -> x1
0.34/0.65	  Unfolding Processor:
0.34/0.65	   loop length: 7
0.34/0.65	   terms:
0.34/0.65	    b(a(c(a(x1821))))
0.34/0.65	    a(a(b(b(c(a(c(a(x1821))))))))
0.34/0.65	    a(a(b(b(c(c(a(x1821)))))))
0.34/0.65	    a(a(b(b(a(x1821)))))
0.34/0.65	    a(a(b(a(a(b(b(c(a(x1821)))))))))
0.34/0.65	    a(a(b(a(b(b(c(a(x1821))))))))
0.34/0.65	    a(a(b(a(b(c(a(x1821)))))))
0.34/0.65	   context: a(a([]))
0.34/0.65	   substitution:
0.34/0.65	    x1821 -> x1821
0.34/0.65	   Qed
0.34/0.65	EOF