0.33/0.49	NO
0.79/0.49	
0.79/0.49	Problem:
0.79/0.49	 a(a(a(x1))) -> a(b(b(x1)))
0.79/0.49	 b(a(b(x1))) -> a(b(a(x1)))
0.79/0.49	
0.79/0.49	Proof:
0.79/0.49	 String Reversal Processor:
0.79/0.49	  a(a(a(x1))) -> b(b(a(x1)))
0.79/0.49	  b(a(b(x1))) -> a(b(a(x1)))
0.79/0.49	  Unfolding Processor:
0.79/0.49	   loop length: 6
0.79/0.49	   terms:
0.79/0.49	    a(a(a(b(a(a(x774))))))
0.79/0.49	    b(b(a(b(a(a(x774))))))
0.79/0.49	    b(a(b(a(a(a(x774))))))
0.79/0.49	    a(b(a(a(a(a(x774))))))
0.79/0.49	    a(b(a(b(b(a(x774))))))
0.79/0.49	    a(a(b(a(b(a(x774))))))
0.79/0.49	   context: []
0.79/0.49	   substitution:
0.79/0.49	    x774 -> x774
0.79/0.49	   Qed
0.79/0.49	EOF