0.34/0.54	YES
0.34/0.54	
0.34/0.54	Problem:
0.34/0.54	 b(a(a(b(b(b(x1)))))) -> a(b(a(b(b(b(a(x1)))))))
0.34/0.54	
0.34/0.54	Proof:
0.34/0.54	 String Reversal Processor:
0.34/0.54	  b(b(b(a(a(b(x1)))))) -> a(b(b(b(a(b(a(x1)))))))
0.34/0.54	  Bounds Processor:
0.34/0.54	   bound: 0
0.34/0.54	   enrichment: match
0.34/0.54	   automaton:
0.34/0.54	    final states: {1}
0.34/0.54	    transitions:
0.34/0.54	     f20() -> 2*
0.34/0.54	     a0(2) -> 3*
0.34/0.54	     a0(4) -> 5*
0.34/0.54	     a0(8) -> 1*
0.34/0.54	     b0(5) -> 6*
0.34/0.54	     b0(7) -> 8*
0.34/0.54	     b0(6) -> 7*
0.34/0.54	     b0(3) -> 4*
0.34/0.54	   problem:
0.34/0.54	    
0.34/0.54	   Qed
0.34/0.55	EOF