1.71/0.75	YES
1.71/0.75	
1.71/0.75	Problem:
1.71/0.75	 b(a(a(b(a(x1))))) -> a(a(b(b(a(a(b(x1)))))))
1.71/0.75	
1.71/0.75	Proof:
1.71/0.75	 String Reversal Processor:
1.71/0.75	  a(b(a(a(b(x1))))) -> b(a(a(b(b(a(a(x1)))))))
1.71/0.75	  Bounds Processor:
1.71/0.75	   bound: 1
1.71/0.75	   enrichment: match
1.71/0.75	   automaton:
1.71/0.75	    final states: {1}
1.71/0.75	    transitions:
1.71/0.75	     f20() -> 2*
1.71/0.75	     b0(5) -> 6*
1.71/0.75	     b0(4) -> 5*
1.71/0.75	     b0(8) -> 1*
1.71/0.75	     a0(7) -> 8*
1.71/0.75	     a0(2) -> 3*
1.71/0.75	     a0(6) -> 7*
1.71/0.75	     a0(3) -> 4*
1.71/0.75	     b1(15) -> 16*
1.71/0.75	     b1(12) -> 13*
1.71/0.75	     b1(11) -> 12*
1.71/0.75	     a1(10) -> 11*
1.71/0.75	     a1(14) -> 15*
1.71/0.75	     a1(9) -> 10*
1.71/0.75	     a1(13) -> 14*
1.71/0.75	     1 -> 10,3
1.71/0.75	     5 -> 9*
1.71/0.75	     16 -> 11,4
1.71/0.75	   problem:
1.71/0.75	    
1.71/0.75	   Qed
1.71/0.75	EOF