0.34/0.57	YES
0.34/0.58	
0.34/0.58	Problem:
0.34/0.58	 b(a(a(a(b(b(x1)))))) -> a(b(a(a(b(b(a(x1)))))))
0.34/0.58	
0.34/0.58	Proof:
0.34/0.58	 String Reversal Processor:
0.34/0.58	  b(b(a(a(a(b(x1)))))) -> a(b(b(a(a(b(a(x1)))))))
0.34/0.58	  Bounds Processor:
0.34/0.58	   bound: 0
0.34/0.58	   enrichment: match
0.34/0.58	   automaton:
0.34/0.58	    final states: {1}
0.34/0.58	    transitions:
0.34/0.58	     f20() -> 2*
0.34/0.58	     a0(5) -> 6*
0.34/0.58	     a0(2) -> 3*
0.34/0.58	     a0(4) -> 5*
0.34/0.58	     a0(8) -> 1*
0.34/0.58	     b0(7) -> 8*
0.34/0.58	     b0(6) -> 7*
0.34/0.58	     b0(3) -> 4*
0.34/0.58	   problem:
0.34/0.58	    
0.34/0.58	   Qed
1.13/0.58	EOF