10.71/3.59 YES 10.97/3.64 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 10.97/3.64 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 10.97/3.64 10.97/3.64 10.97/3.64 Termination w.r.t. Q of the given QTRS could be proven: 10.97/3.64 10.97/3.64 (0) QTRS 10.97/3.64 (1) QTRS Reverse [EQUIVALENT, 0 ms] 10.97/3.64 (2) QTRS 10.97/3.64 (3) QTRSRRRProof [EQUIVALENT, 2 ms] 10.97/3.64 (4) QTRS 10.97/3.64 (5) Overlay + Local Confluence [EQUIVALENT, 0 ms] 10.97/3.64 (6) QTRS 10.97/3.64 (7) DependencyPairsProof [EQUIVALENT, 1 ms] 10.97/3.64 (8) QDP 10.97/3.64 (9) DependencyGraphProof [EQUIVALENT, 1 ms] 10.97/3.64 (10) QDP 10.97/3.64 (11) UsableRulesProof [EQUIVALENT, 0 ms] 10.97/3.64 (12) QDP 10.97/3.64 (13) QReductionProof [EQUIVALENT, 0 ms] 10.97/3.64 (14) QDP 10.97/3.64 (15) QDPSizeChangeProof [EQUIVALENT, 1 ms] 10.97/3.64 (16) YES 10.97/3.64 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (0) 10.97/3.64 Obligation: 10.97/3.64 Q restricted rewrite system: 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(a(x1)) -> b(b(b(x1))) 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 b(b(x1)) -> c(c(c(x1))) 10.97/3.64 c(c(x1)) -> d(d(d(x1))) 10.97/3.64 c(d(d(x1))) -> a(x1) 10.97/3.64 10.97/3.64 Q is empty. 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (1) QTRS Reverse (EQUIVALENT) 10.97/3.64 We applied the QTRS Reverse Processor [REVERSE]. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (2) 10.97/3.64 Obligation: 10.97/3.64 Q restricted rewrite system: 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(a(x1)) -> b(b(b(x1))) 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 b(b(x1)) -> c(c(c(x1))) 10.97/3.64 c(c(x1)) -> d(d(d(x1))) 10.97/3.64 d(d(c(x1))) -> a(x1) 10.97/3.64 10.97/3.64 Q is empty. 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (3) QTRSRRRProof (EQUIVALENT) 10.97/3.64 Used ordering: 10.97/3.64 Polynomial interpretation [POLO]: 10.97/3.64 10.97/3.64 POL(a(x_1)) = 53 + x_1 10.97/3.64 POL(b(x_1)) = 35 + x_1 10.97/3.64 POL(c(x_1)) = 23 + x_1 10.97/3.64 POL(d(x_1)) = 15 + x_1 10.97/3.64 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 10.97/3.64 10.97/3.64 a(a(x1)) -> b(b(b(x1))) 10.97/3.64 b(b(x1)) -> c(c(c(x1))) 10.97/3.64 c(c(x1)) -> d(d(d(x1))) 10.97/3.64 10.97/3.64 10.97/3.64 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (4) 10.97/3.64 Obligation: 10.97/3.64 Q restricted rewrite system: 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 d(d(c(x1))) -> a(x1) 10.97/3.64 10.97/3.64 Q is empty. 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (5) Overlay + Local Confluence (EQUIVALENT) 10.97/3.64 The TRS is overlay and locally confluent. By [NOC] we can switch to innermost. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (6) 10.97/3.64 Obligation: 10.97/3.64 Q restricted rewrite system: 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 d(d(c(x1))) -> a(x1) 10.97/3.64 10.97/3.64 The set Q consists of the following terms: 10.97/3.64 10.97/3.64 a(x0) 10.97/3.64 d(d(c(x0))) 10.97/3.64 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (7) DependencyPairsProof (EQUIVALENT) 10.97/3.64 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (8) 10.97/3.64 Obligation: 10.97/3.64 Q DP problem: 10.97/3.64 The TRS P consists of the following rules: 10.97/3.64 10.97/3.64 A(x1) -> D(c(d(x1))) 10.97/3.64 A(x1) -> D(x1) 10.97/3.64 D(d(c(x1))) -> A(x1) 10.97/3.64 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 d(d(c(x1))) -> a(x1) 10.97/3.64 10.97/3.64 The set Q consists of the following terms: 10.97/3.64 10.97/3.64 a(x0) 10.97/3.64 d(d(c(x0))) 10.97/3.64 10.97/3.64 We have to consider all minimal (P,Q,R)-chains. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (9) DependencyGraphProof (EQUIVALENT) 10.97/3.64 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (10) 10.97/3.64 Obligation: 10.97/3.64 Q DP problem: 10.97/3.64 The TRS P consists of the following rules: 10.97/3.64 10.97/3.64 A(x1) -> D(x1) 10.97/3.64 D(d(c(x1))) -> A(x1) 10.97/3.64 10.97/3.64 The TRS R consists of the following rules: 10.97/3.64 10.97/3.64 a(x1) -> d(c(d(x1))) 10.97/3.64 d(d(c(x1))) -> a(x1) 10.97/3.64 10.97/3.64 The set Q consists of the following terms: 10.97/3.64 10.97/3.64 a(x0) 10.97/3.64 d(d(c(x0))) 10.97/3.64 10.97/3.64 We have to consider all minimal (P,Q,R)-chains. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (11) UsableRulesProof (EQUIVALENT) 10.97/3.64 As all Q-normal forms are R-normal forms we are in the innermost case. Hence, by the usable rules processor [LPAR04] we can delete all non-usable rules [FROCOS05] from R. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (12) 10.97/3.64 Obligation: 10.97/3.64 Q DP problem: 10.97/3.64 The TRS P consists of the following rules: 10.97/3.64 10.97/3.64 A(x1) -> D(x1) 10.97/3.64 D(d(c(x1))) -> A(x1) 10.97/3.64 10.97/3.64 R is empty. 10.97/3.64 The set Q consists of the following terms: 10.97/3.64 10.97/3.64 a(x0) 10.97/3.64 d(d(c(x0))) 10.97/3.64 10.97/3.64 We have to consider all minimal (P,Q,R)-chains. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (13) QReductionProof (EQUIVALENT) 10.97/3.64 We deleted the following terms from Q as each root-symbol of these terms does neither occur in P nor in R.[THIEMANN]. 10.97/3.64 10.97/3.64 a(x0) 10.97/3.64 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (14) 10.97/3.64 Obligation: 10.97/3.64 Q DP problem: 10.97/3.64 The TRS P consists of the following rules: 10.97/3.64 10.97/3.64 A(x1) -> D(x1) 10.97/3.64 D(d(c(x1))) -> A(x1) 10.97/3.64 10.97/3.64 R is empty. 10.97/3.64 The set Q consists of the following terms: 10.97/3.64 10.97/3.64 d(d(c(x0))) 10.97/3.64 10.97/3.64 We have to consider all minimal (P,Q,R)-chains. 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (15) QDPSizeChangeProof (EQUIVALENT) 10.97/3.64 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 10.97/3.64 10.97/3.64 From the DPs we obtained the following set of size-change graphs: 10.97/3.64 *D(d(c(x1))) -> A(x1) 10.97/3.64 The graph contains the following edges 1 > 1 10.97/3.64 10.97/3.64 10.97/3.64 *A(x1) -> D(x1) 10.97/3.64 The graph contains the following edges 1 >= 1 10.97/3.64 10.97/3.64 10.97/3.64 ---------------------------------------- 10.97/3.64 10.97/3.64 (16) 10.97/3.64 YES 11.17/3.72 EOF