0.34/0.50	NO
0.34/0.50	
0.34/0.50	Problem:
0.34/0.50	 c(b(a(b(a(x1))))) -> a(b(a(b(a(b(c(b(c(x1)))))))))
0.34/0.50	
0.34/0.50	Proof:
0.34/0.50	 Unfolding Processor:
0.34/0.50	  loop length: 4
0.34/0.50	  terms:
0.34/0.50	   c(b(a(b(a(b(a(b(a(b(a(b(a(x144)))))))))))))
0.34/0.50	   a(b(a(b(a(b(c(b(c(b(a(b(a(b(a(b(a(x144)))))))))))))))))
0.34/0.50	   a(b(a(b(a(b(c(b(a(b(a(b(a(b(c(b(c(b(a(b(a(x144)))))))))))))))))))))
0.34/0.50	   a(b(a(b(a(b(c(b(a(b(a(b(a(b(c(b(a(b(a(b(a(b(c(b(c(x144)))))))))))))))))))))))))
0.34/0.50	  context: a(b(a(b(a(b([]))))))
0.34/0.50	  substitution:
0.34/0.50	   x144 -> b(c(b(c(b(a(b(c(b(c(x144))))))))))
0.34/0.50	  Qed
0.81/0.51	EOF