1.14/0.58	YES
1.14/0.58	
1.14/0.58	Problem:
1.14/0.58	 b(b(a(b(b(b(x1)))))) -> a(b(b(b(b(b(a(x1)))))))
1.14/0.58	
1.14/0.58	Proof:
1.14/0.58	 String Reversal Processor:
1.14/0.58	  b(b(b(a(b(b(x1)))))) -> a(b(b(b(b(b(a(x1)))))))
1.14/0.58	  Bounds Processor:
1.14/0.58	   bound: 0
1.14/0.58	   enrichment: match
1.14/0.58	   automaton:
1.14/0.58	    final states: {1}
1.14/0.58	    transitions:
1.14/0.58	     f20() -> 2*
1.14/0.58	     a0(2) -> 3*
1.14/0.58	     a0(8) -> 1*
1.14/0.58	     b0(5) -> 6*
1.14/0.58	     b0(7) -> 8*
1.14/0.58	     b0(4) -> 5*
1.14/0.58	     b0(6) -> 7*
1.14/0.58	     b0(3) -> 4*
1.14/0.58	     1 -> 6*
1.14/0.58	   problem:
1.14/0.58	    
1.14/0.58	   Qed
1.14/0.59	EOF