1.95/0.96	YES
1.95/0.96	
1.95/0.96	Problem:
1.95/0.96	 a(x1) -> b(c(x1))
1.95/0.96	 a(b(x1)) -> b(a(x1))
1.95/0.96	 d(c(x1)) -> d(a(x1))
1.95/0.96	 a(c(x1)) -> c(a(x1))
1.95/0.96	
1.95/0.96	Proof:
1.95/0.96	 String Reversal Processor:
1.95/0.96	  a(x1) -> c(b(x1))
1.95/0.96	  b(a(x1)) -> a(b(x1))
1.95/0.96	  c(d(x1)) -> a(d(x1))
1.95/0.96	  c(a(x1)) -> a(c(x1))
1.95/0.96	  Matrix Interpretation Processor: dim=3
1.95/0.96	   
1.95/0.96	   interpretation:
1.95/0.96	              [1 0 0]     [0]
1.95/0.96	    [d](x0) = [0 0 0]x0 + [1]
1.95/0.96	              [0 0 0]     [1],
1.95/0.96	    
1.95/0.96	              [1 0 0]  
1.95/0.96	    [b](x0) = [0 0 0]x0
1.95/0.96	              [0 0 0]  ,
1.95/0.96	    
1.95/0.96	              [1 1 1]  
1.95/0.96	    [c](x0) = [0 1 0]x0
1.95/0.96	              [0 0 1]  ,
1.95/0.96	    
1.95/0.96	              [1 0 0]     [1]
1.95/0.96	    [a](x0) = [0 0 1]x0 + [0]
1.95/0.96	              [0 1 0]     [0]
1.95/0.96	   orientation:
1.95/0.96	            [1 0 0]     [1]    [1 0 0]             
1.95/0.96	    a(x1) = [0 0 1]x1 + [0] >= [0 0 0]x1 = c(b(x1))
1.95/0.96	            [0 1 0]     [0]    [0 0 0]             
1.95/0.96	    
1.95/0.96	               [1 0 0]     [1]    [1 0 0]     [1]           
1.95/0.96	    b(a(x1)) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(x1))
1.95/0.96	               [0 0 0]     [0]    [0 0 0]     [0]           
1.95/0.96	    
1.95/0.96	               [1 0 0]     [2]    [1 0 0]     [1]           
1.95/0.96	    c(d(x1)) = [0 0 0]x1 + [1] >= [0 0 0]x1 + [1] = a(d(x1))
1.95/0.96	               [0 0 0]     [1]    [0 0 0]     [1]           
1.95/0.96	    
1.95/0.96	               [1 1 1]     [1]    [1 1 1]     [1]           
1.95/0.96	    c(a(x1)) = [0 0 1]x1 + [0] >= [0 0 1]x1 + [0] = a(c(x1))
1.95/0.96	               [0 1 0]     [0]    [0 1 0]     [0]           
1.95/0.96	   problem:
1.95/0.96	    b(a(x1)) -> a(b(x1))
1.95/0.96	    c(a(x1)) -> a(c(x1))
1.95/0.96	   KBO Processor:
1.95/0.96	    weight function:
1.95/0.96	     w0 = 1
1.95/0.96	     w(c) = w(a) = 1
1.95/0.96	     w(b) = 0
1.95/0.96	    precedence:
1.95/0.96	     b > c > a
1.95/0.96	    problem:
1.95/0.96	     
1.95/0.96	    Qed
1.95/0.97	EOF