0.34/0.63	YES
0.34/0.63	
0.34/0.63	Problem:
0.34/0.63	 a(a(x1)) -> c(b(x1))
0.34/0.63	 b(b(x1)) -> a(c(x1))
0.34/0.63	 c(c(x1)) -> b(a(x1))
0.34/0.63	
0.34/0.63	Proof:
0.34/0.63	 String Reversal Processor:
0.34/0.63	  a(a(x1)) -> b(c(x1))
0.34/0.63	  b(b(x1)) -> c(a(x1))
0.34/0.63	  c(c(x1)) -> a(b(x1))
0.34/0.63	  Bounds Processor:
0.34/0.63	   bound: 0
0.34/0.63	   enrichment: match
0.34/0.63	   automaton:
0.34/0.63	    final states: {6,4,1}
0.34/0.63	    transitions:
0.34/0.63	     f30() -> 2*
0.34/0.63	     b0(2) -> 7*
0.34/0.63	     b0(3) -> 1*
0.34/0.63	     c0(5) -> 4*
0.34/0.63	     c0(2) -> 3*
0.34/0.63	     a0(7) -> 6*
0.34/0.63	     a0(2) -> 5*
0.34/0.63	     1 -> 5*
0.34/0.63	     4 -> 7*
0.34/0.63	     6 -> 3*
0.34/0.63	   problem:
0.34/0.63	    
0.34/0.63	   Qed
0.34/0.64	EOF