1.33/0.68	YES
1.33/0.68	
1.33/0.68	Problem:
1.33/0.68	 b(a(b(a(a(x1))))) -> a(a(b(b(a(b(a(b(a(x1)))))))))
1.33/0.68	
1.33/0.68	Proof:
1.33/0.68	 String Reversal Processor:
1.33/0.68	  a(a(b(a(b(x1))))) -> a(b(a(b(a(b(b(a(a(x1)))))))))
1.33/0.68	  Bounds Processor:
1.33/0.68	   bound: 1
1.33/0.68	   enrichment: match
1.33/0.68	   automaton:
1.33/0.68	    final states: {1}
1.33/0.68	    transitions:
1.33/0.68	     a1(15) -> 16*
1.33/0.68	     a1(17) -> 18*
1.33/0.68	     a1(12) -> 13*
1.33/0.68	     a1(19) -> 20*
1.33/0.68	     a1(11) -> 12*
1.33/0.68	     b1(14) -> 15*
1.33/0.68	     b1(16) -> 17*
1.33/0.68	     b1(18) -> 19*
1.33/0.68	     b1(13) -> 14*
1.33/0.68	     f20() -> 2*
1.33/0.68	     a0(10) -> 1*
1.33/0.68	     a0(2) -> 3*
1.33/0.68	     a0(6) -> 7*
1.33/0.68	     a0(8) -> 9*
1.33/0.68	     a0(3) -> 4*
1.33/0.68	     b0(5) -> 6*
1.33/0.68	     b0(7) -> 8*
1.33/0.68	     b0(9) -> 10*
1.33/0.68	     b0(4) -> 5*
1.33/0.68	     1 -> 3,4
1.33/0.68	     7 -> 11*
1.33/0.68	     20 -> 4*
1.33/0.68	   problem:
1.33/0.68	    
1.33/0.68	   Qed
1.33/0.69	EOF