1.93/0.81	YES
1.93/0.81	
1.93/0.81	Problem:
1.93/0.81	 a(b(x1)) -> b(a(a(x1)))
1.93/0.81	 b(c(x1)) -> c(b(x1))
1.93/0.81	 a(a(x1)) -> a(c(a(x1)))
1.93/0.81	
1.93/0.81	Proof:
1.93/0.81	 String Reversal Processor:
1.93/0.81	  b(a(x1)) -> a(a(b(x1)))
1.93/0.81	  c(b(x1)) -> b(c(x1))
1.93/0.81	  a(a(x1)) -> a(c(a(x1)))
1.93/0.81	  Bounds Processor:
1.93/0.81	   bound: 2
1.93/0.81	   enrichment: match
1.93/0.81	   automaton:
1.93/0.81	    final states: {7,5,1}
1.93/0.81	    transitions:
1.93/0.81	     f30() -> 2*
1.93/0.81	     a0(2) -> 8*
1.93/0.81	     a0(9) -> 7*
1.93/0.81	     a0(4) -> 1*
1.93/0.81	     a0(3) -> 4*
1.93/0.81	     b0(2) -> 3*
1.93/0.81	     b0(6) -> 5*
1.93/0.81	     c0(2) -> 6*
1.93/0.81	     c0(8) -> 9*
1.93/0.81	     a1(14) -> 15*
1.93/0.81	     a1(26) -> 27*
1.93/0.81	     a1(16) -> 17*
1.93/0.81	     c1(15) -> 16*
1.93/0.81	     a2(22) -> 23*
1.93/0.81	     a2(24) -> 25*
1.93/0.81	     a2(31) -> 32*
1.93/0.81	     c2(30) -> 31*
1.93/0.81	     c2(23) -> 24*
1.93/0.81	     1 -> 3,14
1.93/0.81	     3 -> 14*
1.93/0.81	     4 -> 26*
1.93/0.81	     5 -> 6*
1.93/0.81	     7 -> 8*
1.93/0.81	     16 -> 22*
1.93/0.81	     17 -> 27,1
1.93/0.81	     25 -> 30,4,15
1.93/0.81	     27 -> 23*
1.93/0.81	     32 -> 27*
1.93/0.81	   problem:
1.93/0.81	    
1.93/0.81	   Qed
1.93/0.81	EOF