18.81/5.75 YES 19.00/5.76 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 19.00/5.76 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 19.00/5.76 19.00/5.76 19.00/5.76 Termination w.r.t. Q of the given QTRS could be proven: 19.00/5.76 19.00/5.76 (0) QTRS 19.00/5.76 (1) QTRS Reverse [EQUIVALENT, 0 ms] 19.00/5.76 (2) QTRS 19.00/5.76 (3) DependencyPairsProof [EQUIVALENT, 1 ms] 19.00/5.76 (4) QDP 19.00/5.76 (5) QDPOrderProof [EQUIVALENT, 22 ms] 19.00/5.76 (6) QDP 19.00/5.76 (7) DependencyGraphProof [EQUIVALENT, 0 ms] 19.00/5.76 (8) QDP 19.00/5.76 (9) QDPOrderProof [EQUIVALENT, 37 ms] 19.00/5.76 (10) QDP 19.00/5.76 (11) DependencyGraphProof [EQUIVALENT, 0 ms] 19.00/5.76 (12) TRUE 19.00/5.76 19.00/5.76 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (0) 19.00/5.76 Obligation: 19.00/5.76 Q restricted rewrite system: 19.00/5.76 The TRS R consists of the following rules: 19.00/5.76 19.00/5.76 a(a(x1)) -> c(b(x1)) 19.00/5.76 b(b(x1)) -> c(a(x1)) 19.00/5.76 c(c(x1)) -> b(a(x1)) 19.00/5.76 19.00/5.76 Q is empty. 19.00/5.76 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (1) QTRS Reverse (EQUIVALENT) 19.00/5.76 We applied the QTRS Reverse Processor [REVERSE]. 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (2) 19.00/5.76 Obligation: 19.00/5.76 Q restricted rewrite system: 19.00/5.76 The TRS R consists of the following rules: 19.00/5.76 19.00/5.76 a(a(x1)) -> b(c(x1)) 19.00/5.76 b(b(x1)) -> a(c(x1)) 19.00/5.76 c(c(x1)) -> a(b(x1)) 19.00/5.76 19.00/5.76 Q is empty. 19.00/5.76 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (3) DependencyPairsProof (EQUIVALENT) 19.00/5.76 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (4) 19.00/5.76 Obligation: 19.00/5.76 Q DP problem: 19.00/5.76 The TRS P consists of the following rules: 19.00/5.76 19.00/5.76 A(a(x1)) -> B(c(x1)) 19.00/5.76 A(a(x1)) -> C(x1) 19.00/5.76 B(b(x1)) -> A(c(x1)) 19.00/5.76 B(b(x1)) -> C(x1) 19.00/5.76 C(c(x1)) -> A(b(x1)) 19.00/5.76 C(c(x1)) -> B(x1) 19.00/5.76 19.00/5.76 The TRS R consists of the following rules: 19.00/5.76 19.00/5.76 a(a(x1)) -> b(c(x1)) 19.00/5.76 b(b(x1)) -> a(c(x1)) 19.00/5.76 c(c(x1)) -> a(b(x1)) 19.00/5.76 19.00/5.76 Q is empty. 19.00/5.76 We have to consider all minimal (P,Q,R)-chains. 19.00/5.76 ---------------------------------------- 19.00/5.76 19.00/5.76 (5) QDPOrderProof (EQUIVALENT) 19.00/5.76 We use the reduction pair processor [LPAR04,JAR06]. 19.00/5.76 19.00/5.76 19.00/5.76 The following pairs can be oriented strictly and are deleted. 19.00/5.76 19.00/5.76 A(a(x1)) -> C(x1) 19.00/5.76 B(b(x1)) -> C(x1) 19.00/5.76 C(c(x1)) -> B(x1) 19.00/5.76 The remaining pairs can at least be oriented weakly. 19.00/5.76 Used ordering: Polynomial interpretation [POLO]: 19.00/5.76 19.00/5.76 POL(A(x_1)) = 1 + x_1 19.00/5.77 POL(B(x_1)) = 1 + x_1 19.00/5.77 POL(C(x_1)) = 1 + x_1 19.00/5.77 POL(a(x_1)) = 1 + x_1 19.00/5.77 POL(b(x_1)) = 1 + x_1 19.00/5.77 POL(c(x_1)) = 1 + x_1 19.00/5.77 19.00/5.77 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 19.00/5.77 19.00/5.77 c(c(x1)) -> a(b(x1)) 19.00/5.77 b(b(x1)) -> a(c(x1)) 19.00/5.77 a(a(x1)) -> b(c(x1)) 19.00/5.77 19.00/5.77 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (6) 19.00/5.77 Obligation: 19.00/5.77 Q DP problem: 19.00/5.77 The TRS P consists of the following rules: 19.00/5.77 19.00/5.77 A(a(x1)) -> B(c(x1)) 19.00/5.77 B(b(x1)) -> A(c(x1)) 19.00/5.77 C(c(x1)) -> A(b(x1)) 19.00/5.77 19.00/5.77 The TRS R consists of the following rules: 19.00/5.77 19.00/5.77 a(a(x1)) -> b(c(x1)) 19.00/5.77 b(b(x1)) -> a(c(x1)) 19.00/5.77 c(c(x1)) -> a(b(x1)) 19.00/5.77 19.00/5.77 Q is empty. 19.00/5.77 We have to consider all minimal (P,Q,R)-chains. 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (7) DependencyGraphProof (EQUIVALENT) 19.00/5.77 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (8) 19.00/5.77 Obligation: 19.00/5.77 Q DP problem: 19.00/5.77 The TRS P consists of the following rules: 19.00/5.77 19.00/5.77 B(b(x1)) -> A(c(x1)) 19.00/5.77 A(a(x1)) -> B(c(x1)) 19.00/5.77 19.00/5.77 The TRS R consists of the following rules: 19.00/5.77 19.00/5.77 a(a(x1)) -> b(c(x1)) 19.00/5.77 b(b(x1)) -> a(c(x1)) 19.00/5.77 c(c(x1)) -> a(b(x1)) 19.00/5.77 19.00/5.77 Q is empty. 19.00/5.77 We have to consider all minimal (P,Q,R)-chains. 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (9) QDPOrderProof (EQUIVALENT) 19.00/5.77 We use the reduction pair processor [LPAR04,JAR06]. 19.00/5.77 19.00/5.77 19.00/5.77 The following pairs can be oriented strictly and are deleted. 19.00/5.77 19.00/5.77 A(a(x1)) -> B(c(x1)) 19.00/5.77 The remaining pairs can at least be oriented weakly. 19.00/5.77 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 19.00/5.77 19.00/5.77 <<< 19.00/5.77 POL(B(x_1)) = [[-I]] + [[0A, -I, -I]] * x_1 19.00/5.77 >>> 19.00/5.77 19.00/5.77 <<< 19.00/5.77 POL(b(x_1)) = [[1A], [0A], [1A]] + [[1A, 0A, 0A], [0A, -I, -I], [0A, -I, -I]] * x_1 19.00/5.77 >>> 19.00/5.77 19.00/5.77 <<< 19.00/5.77 POL(A(x_1)) = [[0A]] + [[0A, -I, 0A]] * x_1 19.00/5.77 >>> 19.00/5.77 19.00/5.77 <<< 19.00/5.77 POL(c(x_1)) = [[0A], [1A], [0A]] + [[-I, 0A, -I], [1A, 0A, 0A], [0A, 0A, 0A]] * x_1 19.00/5.77 >>> 19.00/5.77 19.00/5.77 <<< 19.00/5.77 POL(a(x_1)) = [[0A], [0A], [1A]] + [[0A, 1A, 0A], [0A, 0A, 0A], [0A, 0A, 0A]] * x_1 19.00/5.77 >>> 19.00/5.77 19.00/5.77 19.00/5.77 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 19.00/5.77 19.00/5.77 c(c(x1)) -> a(b(x1)) 19.00/5.77 b(b(x1)) -> a(c(x1)) 19.00/5.77 a(a(x1)) -> b(c(x1)) 19.00/5.77 19.00/5.77 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (10) 19.00/5.77 Obligation: 19.00/5.77 Q DP problem: 19.00/5.77 The TRS P consists of the following rules: 19.00/5.77 19.00/5.77 B(b(x1)) -> A(c(x1)) 19.00/5.77 19.00/5.77 The TRS R consists of the following rules: 19.00/5.77 19.00/5.77 a(a(x1)) -> b(c(x1)) 19.00/5.77 b(b(x1)) -> a(c(x1)) 19.00/5.77 c(c(x1)) -> a(b(x1)) 19.00/5.77 19.00/5.77 Q is empty. 19.00/5.77 We have to consider all minimal (P,Q,R)-chains. 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (11) DependencyGraphProof (EQUIVALENT) 19.00/5.77 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node. 19.00/5.77 ---------------------------------------- 19.00/5.77 19.00/5.77 (12) 19.00/5.77 TRUE 19.00/5.84 EOF