1.41/0.75	YES
1.41/0.75	
1.41/0.75	Problem:
1.41/0.75	 a(b(a(a(x1)))) -> c(b(a(b(a(x1)))))
1.41/0.75	 a(c(b(x1))) -> a(a(b(c(b(a(x1))))))
1.41/0.75	
1.41/0.75	Proof:
1.41/0.75	 Bounds Processor:
1.41/0.75	  bound: 1
1.41/0.75	  enrichment: match
1.41/0.75	  automaton:
1.41/0.75	   final states: {7,1}
1.41/0.75	   transitions:
1.41/0.75	    f30() -> 2*
1.41/0.75	    c0(4) -> 8*
1.41/0.75	    c0(6) -> 1*
1.41/0.75	    b0(5) -> 6*
1.41/0.75	    b0(8) -> 9*
1.41/0.75	    b0(3) -> 4*
1.41/0.75	    a0(10) -> 7*
1.41/0.75	    a0(2) -> 3*
1.41/0.75	    a0(9) -> 10*
1.41/0.75	    a0(4) -> 5*
1.41/0.75	    c1(15) -> 16*
1.41/0.75	    b1(12) -> 13*
1.41/0.75	    b1(14) -> 15*
1.41/0.75	    a1(11) -> 12*
1.41/0.75	    a1(13) -> 14*
1.41/0.75	    1 -> 3,5
1.41/0.75	    7 -> 3*
1.41/0.75	    9 -> 11*
1.41/0.75	    16 -> 5*
1.41/0.75	  problem:
1.41/0.75	   
1.41/0.75	  Qed
1.41/0.75	EOF