10.59/8.85	MAYBE
10.59/8.85	Input TRS:
10.59/8.85	    1: a(b(b(c(a(a(a(a(x1)))))))) -> a(a(a(a(a(b(b(c(a(a(a(b(b(c(x1))))))))))))))
10.59/8.85	Number of strict rules: 1
10.59/8.85	Direct POLO(bPol) ... failed.
10.59/8.85	Uncurrying ... failed.
10.59/8.85	Dependency Pairs:
10.59/8.85	   #1: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(a(a(a(b(b(c(a(a(a(b(b(c(x1))))))))))))))
10.59/8.85	   #2: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(a(a(b(b(c(a(a(a(b(b(c(x1)))))))))))))
10.59/8.85	   #3: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(a(b(b(c(a(a(a(b(b(c(x1))))))))))))
10.59/8.85	   #4: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(b(b(c(a(a(a(b(b(c(x1)))))))))))
10.59/8.85	   #5: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(b(b(c(a(a(a(b(b(c(x1))))))))))
10.59/8.85	   #6: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(a(b(b(c(x1))))))
10.59/8.85	   #7: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(a(b(b(c(x1)))))
10.59/8.85	   #8: #a(b(b(c(a(a(a(a(x1)))))))) -> #a(b(b(c(x1))))
10.59/8.85	Number of SCCs: 1, DPs: 2
10.59/8.85	  SCC { #5 #8 }
10.59/8.85	POLO(Sum)... POLO(max)... QLPOS... POLO(mSum)... QWPOpS(mSum)... Mat2b... failed.
10.59/8.85	Finding a loop...  failed.
10.59/8.86	EOF