4.49/1.98 YES 4.95/2.03 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 4.95/2.03 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.95/2.03 4.95/2.03 4.95/2.03 Termination w.r.t. Q of the given QTRS could be proven: 4.95/2.03 4.95/2.03 (0) QTRS 4.95/2.03 (1) QTRS Reverse [EQUIVALENT, 0 ms] 4.95/2.03 (2) QTRS 4.95/2.03 (3) Strip Symbols Proof [SOUND, 0 ms] 4.95/2.03 (4) QTRS 4.95/2.03 (5) RFCMatchBoundsTRSProof [EQUIVALENT, 5 ms] 4.95/2.03 (6) YES 4.95/2.03 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (0) 4.95/2.03 Obligation: 4.95/2.03 Q restricted rewrite system: 4.95/2.03 The TRS R consists of the following rules: 4.95/2.03 4.95/2.03 a(b(a(a(a(a(x1)))))) -> a(a(a(a(a(b(a(b(a(a(b(a(a(b(x1)))))))))))))) 4.95/2.03 4.95/2.03 Q is empty. 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (1) QTRS Reverse (EQUIVALENT) 4.95/2.03 We applied the QTRS Reverse Processor [REVERSE]. 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (2) 4.95/2.03 Obligation: 4.95/2.03 Q restricted rewrite system: 4.95/2.03 The TRS R consists of the following rules: 4.95/2.03 4.95/2.03 a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(b(a(b(a(a(a(a(a(x1)))))))))))))) 4.95/2.03 4.95/2.03 Q is empty. 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (3) Strip Symbols Proof (SOUND) 4.95/2.03 We were given the following TRS: 4.95/2.03 4.95/2.03 a(a(a(a(b(a(x1)))))) -> b(a(a(b(a(a(b(a(b(a(a(a(a(a(x1)))))))))))))) 4.95/2.03 4.95/2.03 By stripping symbols from the only rule of the system, we obtained the following TRS [ENDRULLIS]: 4.95/2.03 4.95/2.03 a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(b(a(a(a(a(x))))))))))))) 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (4) 4.95/2.03 Obligation: 4.95/2.03 Q restricted rewrite system: 4.95/2.03 The TRS R consists of the following rules: 4.95/2.03 4.95/2.03 a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(b(a(a(a(a(x))))))))))))) 4.95/2.03 4.95/2.03 Q is empty. 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (5) RFCMatchBoundsTRSProof (EQUIVALENT) 4.95/2.03 Termination of the TRS R could be shown with a Match Bound [MATCHBOUNDS1,MATCHBOUNDS2] of 1. This implies Q-termination of R. 4.95/2.03 The following rules were used to construct the certificate: 4.95/2.03 4.95/2.03 a(a(a(a(b(x))))) -> b(a(a(b(a(a(b(a(b(a(a(a(a(x))))))))))))) 4.95/2.03 4.95/2.03 The certificate found is represented by the following graph. 4.95/2.03 The certificate consists of the following enumerated nodes: 4.95/2.03 421, 422, 527, 528, 529, 530, 531, 532, 533, 534, 535, 536, 537, 538, 544, 545, 546, 547, 548, 549, 550, 551, 552, 553, 554, 555 4.95/2.03 4.95/2.03 Node 421 is start node and node 422 is final node. 4.95/2.03 4.95/2.03 Those nodes are connected through the following edges: 4.95/2.03 4.95/2.03 * 421 to 527 labelled b_1(0)* 422 to 422 labelled #_1(0)* 527 to 528 labelled a_1(0)* 528 to 529 labelled a_1(0)* 529 to 530 labelled b_1(0)* 530 to 531 labelled a_1(0)* 531 to 532 labelled a_1(0)* 532 to 533 labelled b_1(0)* 533 to 534 labelled a_1(0)* 534 to 535 labelled b_1(0)* 535 to 536 labelled a_1(0)* 535 to 544 labelled b_1(1)* 536 to 537 labelled a_1(0)* 536 to 544 labelled b_1(1)* 537 to 538 labelled a_1(0)* 537 to 544 labelled b_1(1)* 538 to 422 labelled a_1(0)* 538 to 544 labelled b_1(1)* 544 to 545 labelled a_1(1)* 545 to 546 labelled a_1(1)* 546 to 547 labelled b_1(1)* 547 to 548 labelled a_1(1)* 548 to 549 labelled a_1(1)* 549 to 550 labelled b_1(1)* 550 to 551 labelled a_1(1)* 551 to 552 labelled b_1(1)* 552 to 553 labelled a_1(1)* 552 to 544 labelled b_1(1)* 553 to 554 labelled a_1(1)* 553 to 544 labelled b_1(1)* 554 to 555 labelled a_1(1)* 554 to 544 labelled b_1(1)* 555 to 422 labelled a_1(1)* 555 to 544 labelled b_1(1) 4.95/2.03 4.95/2.03 4.95/2.03 ---------------------------------------- 4.95/2.03 4.95/2.03 (6) 4.95/2.03 YES 4.95/2.08 EOF