5.25/1.78	NO
5.25/1.78	
5.25/1.78	Problem:
5.25/1.78	 a(a(b(x1))) -> b(b(c(a(a(x1)))))
5.25/1.78	 a(c(x1)) -> a(a(x1))
5.25/1.78	
5.25/1.78	Proof:
5.25/1.78	 String Reversal Processor:
5.25/1.78	  b(a(a(x1))) -> a(a(c(b(b(x1)))))
5.25/1.78	  c(a(x1)) -> a(a(x1))
5.25/1.78	  Unfolding Processor:
5.25/1.78	   loop length: 11
5.25/1.78	   terms:
5.25/1.78	    b(a(a(a(a(a(a(a(a(x29288)))))))))
5.25/1.78	    a(a(c(b(b(a(a(a(a(a(a(x29288)))))))))))
5.25/1.78	    a(a(c(b(a(a(c(b(b(a(a(a(a(x29288)))))))))))))
5.25/1.78	    a(a(c(b(a(a(c(b(a(a(c(b(b(a(a(x29288)))))))))))))))
5.25/1.78	    a(a(c(b(a(a(c(a(a(c(b(b(c(b(b(a(a(x29288)))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(b(b(c(b(b(a(a(x29288)))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(b(b(c(b(a(a(c(b(b(x29288)))))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(b(b(c(a(a(c(b(b(c(b(b(x29288)))))))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(b(b(a(a(a(c(b(b(c(b(b(x29288)))))))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(b(a(a(c(b(b(a(c(b(b(c(b(b(x29288)))))))))))))))))))))))
5.25/1.78	    a(a(c(b(a(a(a(a(a(c(a(a(c(b(b(c(b(b(a(c(b(b(c(b(b(x29288)))))))))))))))))))))))))
5.25/1.78	   context: a(a(c([])))
5.25/1.78	   substitution:
5.25/1.78	    x29288 -> c(b(b(c(b(b(a(c(b(b(c(b(b(x29288)))))))))))))
5.25/1.78	   Qed
5.25/1.78	EOF