17.92/5.46 YES 17.98/5.49 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 17.98/5.49 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 17.98/5.49 17.98/5.49 17.98/5.49 Termination w.r.t. Q of the given QTRS could be proven: 17.98/5.49 17.98/5.49 (0) QTRS 17.98/5.49 (1) DependencyPairsProof [EQUIVALENT, 12 ms] 17.98/5.49 (2) QDP 17.98/5.49 (3) QDPOrderProof [EQUIVALENT, 120 ms] 17.98/5.49 (4) QDP 17.98/5.49 (5) UsableRulesProof [EQUIVALENT, 0 ms] 17.98/5.49 (6) QDP 17.98/5.49 (7) QDPSizeChangeProof [EQUIVALENT, 0 ms] 17.98/5.49 (8) YES 17.98/5.49 17.98/5.49 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (0) 17.98/5.49 Obligation: 17.98/5.49 Q restricted rewrite system: 17.98/5.49 The TRS R consists of the following rules: 17.98/5.49 17.98/5.49 a(b(b(x1))) -> b(a(a(a(x1)))) 17.98/5.49 a(a(b(x1))) -> b(a(b(x1))) 17.98/5.49 17.98/5.49 Q is empty. 17.98/5.49 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (1) DependencyPairsProof (EQUIVALENT) 17.98/5.49 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (2) 17.98/5.49 Obligation: 17.98/5.49 Q DP problem: 17.98/5.49 The TRS P consists of the following rules: 17.98/5.49 17.98/5.49 A(b(b(x1))) -> A(a(a(x1))) 17.98/5.49 A(b(b(x1))) -> A(a(x1)) 17.98/5.49 A(b(b(x1))) -> A(x1) 17.98/5.49 17.98/5.49 The TRS R consists of the following rules: 17.98/5.49 17.98/5.49 a(b(b(x1))) -> b(a(a(a(x1)))) 17.98/5.49 a(a(b(x1))) -> b(a(b(x1))) 17.98/5.49 17.98/5.49 Q is empty. 17.98/5.49 We have to consider all minimal (P,Q,R)-chains. 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (3) QDPOrderProof (EQUIVALENT) 17.98/5.49 We use the reduction pair processor [LPAR04,JAR06]. 17.98/5.49 17.98/5.49 17.98/5.49 The following pairs can be oriented strictly and are deleted. 17.98/5.49 17.98/5.49 A(b(b(x1))) -> A(a(a(x1))) 17.98/5.49 A(b(b(x1))) -> A(a(x1)) 17.98/5.49 The remaining pairs can at least be oriented weakly. 17.98/5.49 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 17.98/5.49 17.98/5.49 <<< 17.98/5.49 POL(A(x_1)) = [[0A]] + [[0A, 0A, -I]] * x_1 17.98/5.49 >>> 17.98/5.49 17.98/5.49 <<< 17.98/5.49 POL(b(x_1)) = [[0A], [1A], [-I]] + [[-I, -I, -I], [-I, -I, 0A], [0A, 1A, -I]] * x_1 17.98/5.49 >>> 17.98/5.49 17.98/5.49 <<< 17.98/5.49 POL(a(x_1)) = [[0A], [-I], [0A]] + [[-I, 0A, -I], [-I, 0A, -I], [1A, 0A, -I]] * x_1 17.98/5.49 >>> 17.98/5.49 17.98/5.49 17.98/5.49 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 17.98/5.49 17.98/5.49 a(b(b(x1))) -> b(a(a(a(x1)))) 17.98/5.49 a(a(b(x1))) -> b(a(b(x1))) 17.98/5.49 17.98/5.49 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (4) 17.98/5.49 Obligation: 17.98/5.49 Q DP problem: 17.98/5.49 The TRS P consists of the following rules: 17.98/5.49 17.98/5.49 A(b(b(x1))) -> A(x1) 17.98/5.49 17.98/5.49 The TRS R consists of the following rules: 17.98/5.49 17.98/5.49 a(b(b(x1))) -> b(a(a(a(x1)))) 17.98/5.49 a(a(b(x1))) -> b(a(b(x1))) 17.98/5.49 17.98/5.49 Q is empty. 17.98/5.49 We have to consider all minimal (P,Q,R)-chains. 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (5) UsableRulesProof (EQUIVALENT) 17.98/5.49 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (6) 17.98/5.49 Obligation: 17.98/5.49 Q DP problem: 17.98/5.49 The TRS P consists of the following rules: 17.98/5.49 17.98/5.49 A(b(b(x1))) -> A(x1) 17.98/5.49 17.98/5.49 R is empty. 17.98/5.49 Q is empty. 17.98/5.49 We have to consider all minimal (P,Q,R)-chains. 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (7) QDPSizeChangeProof (EQUIVALENT) 17.98/5.49 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 17.98/5.49 17.98/5.49 From the DPs we obtained the following set of size-change graphs: 17.98/5.49 *A(b(b(x1))) -> A(x1) 17.98/5.49 The graph contains the following edges 1 > 1 17.98/5.49 17.98/5.49 17.98/5.49 ---------------------------------------- 17.98/5.49 17.98/5.49 (8) 17.98/5.49 YES 18.20/5.56 EOF