12.87/3.65 YES 12.87/3.65 12.87/3.65 Problem: 12.87/3.65 c(b(a(a(x1)))) -> a(a(b(c(x1)))) 12.87/3.65 b(a(a(a(x1)))) -> a(a(a(b(x1)))) 12.87/3.65 a(b(c(x1))) -> c(b(a(x1))) 12.87/3.65 c(c(b(b(x1)))) -> b(b(c(c(x1)))) 12.87/3.65 12.87/3.65 Proof: 12.87/3.65 Matrix Interpretation Processor: dim=3 12.87/3.65 12.87/3.65 interpretation: 12.87/3.65 [0] 12.87/3.65 [c](x0) = x0 + [0] 12.87/3.65 [1], 12.87/3.65 12.87/3.65 [1 1 0] 12.87/3.65 [b](x0) = [0 1 0]x0 12.87/3.65 [0 0 1] , 12.87/3.65 12.87/3.65 [1 0 1] [0] 12.87/3.65 [a](x0) = [0 1 0]x0 + [1] 12.87/3.65 [0 0 1] [0] 12.87/3.65 orientation: 12.87/3.65 [1 1 2] [2] [1 1 2] [2] 12.87/3.65 c(b(a(a(x1)))) = [0 1 0]x1 + [2] >= [0 1 0]x1 + [2] = a(a(b(c(x1)))) 12.87/3.65 [0 0 1] [1] [0 0 1] [1] 12.87/3.65 12.87/3.65 [1 1 3] [3] [1 1 3] [0] 12.87/3.65 b(a(a(a(x1)))) = [0 1 0]x1 + [3] >= [0 1 0]x1 + [3] = a(a(a(b(x1)))) 12.87/3.65 [0 0 1] [0] [0 0 1] [0] 12.87/3.65 12.87/3.65 [1 1 1] [1] [1 1 1] [1] 12.87/3.65 a(b(c(x1))) = [0 1 0]x1 + [1] >= [0 1 0]x1 + [1] = c(b(a(x1))) 12.87/3.65 [0 0 1] [1] [0 0 1] [1] 12.87/3.65 12.87/3.65 [1 2 0] [0] [1 2 0] [0] 12.87/3.65 c(c(b(b(x1)))) = [0 1 0]x1 + [0] >= [0 1 0]x1 + [0] = b(b(c(c(x1)))) 12.87/3.65 [0 0 1] [2] [0 0 1] [2] 12.87/3.65 problem: 12.87/3.65 c(b(a(a(x1)))) -> a(a(b(c(x1)))) 12.87/3.65 a(b(c(x1))) -> c(b(a(x1))) 12.87/3.65 c(c(b(b(x1)))) -> b(b(c(c(x1)))) 12.87/3.65 Matrix Interpretation Processor: dim=3 12.87/3.65 12.87/3.65 interpretation: 12.87/3.65 [1 0 0] 12.87/3.65 [c](x0) = [0 0 1]x0 12.87/3.65 [0 1 0] , 12.87/3.65 12.87/3.65 [1 1 0] [0] 12.87/3.65 [b](x0) = [0 0 1]x0 + [0] 12.87/3.65 [1 1 0] [1], 12.87/3.65 12.87/3.65 [1 0 1] [0] 12.87/3.65 [a](x0) = [1 0 1]x0 + [0] 12.87/3.65 [0 0 0] [1] 12.87/3.65 orientation: 12.87/3.65 [2 0 2] [2] [2 0 2] [2] 12.87/3.65 c(b(a(a(x1)))) = [2 0 2]x1 + [3] >= [2 0 2]x1 + [2] = a(a(b(c(x1)))) 12.87/3.65 [0 0 0] [1] [0 0 0] [1] 12.87/3.65 12.87/3.65 [2 0 2] [1] [2 0 2] [0] 12.87/3.65 a(b(c(x1))) = [2 0 2]x1 + [1] >= [2 0 2]x1 + [1] = c(b(a(x1))) 12.87/3.65 [0 0 0] [1] [0 0 0] [1] 12.87/3.65 12.87/3.65 [1 1 1] [0] [1 1 1] [0] 12.87/3.65 c(c(b(b(x1)))) = [1 1 0]x1 + [1] >= [1 1 0]x1 + [1] = b(b(c(c(x1)))) 12.87/3.65 [1 1 1] [1] [1 1 1] [1] 12.87/3.65 problem: 12.87/3.65 c(b(a(a(x1)))) -> a(a(b(c(x1)))) 12.87/3.65 c(c(b(b(x1)))) -> b(b(c(c(x1)))) 12.87/3.65 KBO Processor: 12.87/3.65 weight function: 12.87/3.65 w0 = 1 12.87/3.65 w(c) = w(b) = w(a) = 1 12.87/3.65 precedence: 12.87/3.65 c > b ~ a 12.87/3.65 problem: 12.87/3.65 12.87/3.65 Qed 13.01/3.66 EOF