26.76/7.74 YES 27.28/7.82 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 27.28/7.82 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 27.28/7.82 27.28/7.82 27.28/7.82 Termination w.r.t. Q of the given QTRS could be proven: 27.28/7.82 27.28/7.82 (0) QTRS 27.28/7.82 (1) DependencyPairsProof [EQUIVALENT, 25 ms] 27.28/7.82 (2) QDP 27.28/7.82 (3) MRRProof [EQUIVALENT, 71 ms] 27.28/7.82 (4) QDP 27.28/7.82 (5) QDPOrderProof [EQUIVALENT, 55 ms] 27.28/7.82 (6) QDP 27.28/7.82 (7) QDPOrderProof [EQUIVALENT, 389 ms] 27.28/7.82 (8) QDP 27.28/7.82 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 27.28/7.82 (10) TRUE 27.28/7.82 27.28/7.82 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (0) 27.28/7.82 Obligation: 27.28/7.82 Q restricted rewrite system: 27.28/7.82 The TRS R consists of the following rules: 27.28/7.82 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 27.28/7.82 Q is empty. 27.28/7.82 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (1) DependencyPairsProof (EQUIVALENT) 27.28/7.82 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (2) 27.28/7.82 Obligation: 27.28/7.82 Q DP problem: 27.28/7.82 The TRS P consists of the following rules: 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> B(a(a(b(x1)))) 27.28/7.82 A(b(b(a(x1)))) -> A(a(b(x1))) 27.28/7.82 A(b(b(a(x1)))) -> A(b(x1)) 27.28/7.82 A(b(b(a(x1)))) -> B(x1) 27.28/7.82 B(a(b(x1))) -> A(b(b(b(x1)))) 27.28/7.82 B(a(b(x1))) -> B(b(b(x1))) 27.28/7.82 B(a(b(x1))) -> B(b(x1)) 27.28/7.82 27.28/7.82 The TRS R consists of the following rules: 27.28/7.82 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 27.28/7.82 Q is empty. 27.28/7.82 We have to consider all minimal (P,Q,R)-chains. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (3) MRRProof (EQUIVALENT) 27.28/7.82 By using the rule removal processor [LPAR04] with the following ordering, at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented. 27.28/7.82 27.28/7.82 Strictly oriented dependency pairs: 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> A(b(x1)) 27.28/7.82 A(b(b(a(x1)))) -> B(x1) 27.28/7.82 B(a(b(x1))) -> B(b(b(x1))) 27.28/7.82 B(a(b(x1))) -> B(b(x1)) 27.28/7.82 27.28/7.82 27.28/7.82 Used ordering: Polynomial interpretation [POLO]: 27.28/7.82 27.28/7.82 POL(A(x_1)) = 2 + 2*x_1 27.28/7.82 POL(B(x_1)) = 2*x_1 27.28/7.82 POL(a(x_1)) = 1 + x_1 27.28/7.82 POL(b(x_1)) = x_1 27.28/7.82 27.28/7.82 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (4) 27.28/7.82 Obligation: 27.28/7.82 Q DP problem: 27.28/7.82 The TRS P consists of the following rules: 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> B(a(a(b(x1)))) 27.28/7.82 A(b(b(a(x1)))) -> A(a(b(x1))) 27.28/7.82 B(a(b(x1))) -> A(b(b(b(x1)))) 27.28/7.82 27.28/7.82 The TRS R consists of the following rules: 27.28/7.82 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 27.28/7.82 Q is empty. 27.28/7.82 We have to consider all minimal (P,Q,R)-chains. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (5) QDPOrderProof (EQUIVALENT) 27.28/7.82 We use the reduction pair processor [LPAR04,JAR06]. 27.28/7.82 27.28/7.82 27.28/7.82 The following pairs can be oriented strictly and are deleted. 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> A(a(b(x1))) 27.28/7.82 The remaining pairs can at least be oriented weakly. 27.28/7.82 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(A(x_1)) = [[0A]] + [[-I, -I, 0A]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(b(x_1)) = [[1A], [-I], [0A]] + [[0A, 0A, 0A], [-I, 0A, -I], [0A, -I, 0A]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(a(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, 0A], [0A, 0A, -I], [-I, -I, -I]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(B(x_1)) = [[-I]] + [[0A, 0A, 0A]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 27.28/7.82 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 27.28/7.82 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 27.28/7.82 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (6) 27.28/7.82 Obligation: 27.28/7.82 Q DP problem: 27.28/7.82 The TRS P consists of the following rules: 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> B(a(a(b(x1)))) 27.28/7.82 B(a(b(x1))) -> A(b(b(b(x1)))) 27.28/7.82 27.28/7.82 The TRS R consists of the following rules: 27.28/7.82 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 27.28/7.82 Q is empty. 27.28/7.82 We have to consider all minimal (P,Q,R)-chains. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (7) QDPOrderProof (EQUIVALENT) 27.28/7.82 We use the reduction pair processor [LPAR04,JAR06]. 27.28/7.82 27.28/7.82 27.28/7.82 The following pairs can be oriented strictly and are deleted. 27.28/7.82 27.28/7.82 B(a(b(x1))) -> A(b(b(b(x1)))) 27.28/7.82 The remaining pairs can at least be oriented weakly. 27.28/7.82 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(A(x_1)) = [[-I]] + [[0A, 0A, -I]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(b(x_1)) = [[-I], [0A], [0A]] + [[0A, 0A, 0A], [0A, -I, -I], [0A, 0A, 0A]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(a(x_1)) = [[0A], [0A], [1A]] + [[-I, 0A, -I], [-I, -I, -I], [1A, 0A, -I]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 <<< 27.28/7.82 POL(B(x_1)) = [[-I]] + [[0A, 0A, 0A]] * x_1 27.28/7.82 >>> 27.28/7.82 27.28/7.82 27.28/7.82 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 27.28/7.82 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 27.28/7.82 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (8) 27.28/7.82 Obligation: 27.28/7.82 Q DP problem: 27.28/7.82 The TRS P consists of the following rules: 27.28/7.82 27.28/7.82 A(b(b(a(x1)))) -> B(a(a(b(x1)))) 27.28/7.82 27.28/7.82 The TRS R consists of the following rules: 27.28/7.82 27.28/7.82 a(b(b(a(x1)))) -> b(a(a(b(x1)))) 27.28/7.82 b(a(b(x1))) -> a(b(b(b(x1)))) 27.28/7.82 27.28/7.82 Q is empty. 27.28/7.82 We have to consider all minimal (P,Q,R)-chains. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (9) DependencyGraphProof (EQUIVALENT) 27.28/7.82 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node. 27.28/7.82 ---------------------------------------- 27.28/7.82 27.28/7.82 (10) 27.28/7.82 TRUE 27.45/7.88 EOF