20.89/6.21 YES 21.11/6.23 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 21.11/6.23 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 21.11/6.23 21.11/6.23 21.11/6.23 Termination w.r.t. Q of the given QTRS could be proven: 21.11/6.23 21.11/6.23 (0) QTRS 21.11/6.23 (1) DependencyPairsProof [EQUIVALENT, 0 ms] 21.11/6.23 (2) QDP 21.11/6.23 (3) QDPOrderProof [EQUIVALENT, 132 ms] 21.11/6.23 (4) QDP 21.11/6.23 (5) QDPOrderProof [EQUIVALENT, 30 ms] 21.11/6.23 (6) QDP 21.11/6.23 (7) PisEmptyProof [EQUIVALENT, 0 ms] 21.11/6.23 (8) YES 21.11/6.23 21.11/6.23 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (0) 21.11/6.23 Obligation: 21.11/6.23 Q restricted rewrite system: 21.11/6.23 The TRS R consists of the following rules: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 Q is empty. 21.11/6.23 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (1) DependencyPairsProof (EQUIVALENT) 21.11/6.23 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (2) 21.11/6.23 Obligation: 21.11/6.23 Q DP problem: 21.11/6.23 The TRS P consists of the following rules: 21.11/6.23 21.11/6.23 A(b(b(x1))) -> A(a(x1)) 21.11/6.23 A(b(b(x1))) -> A(x1) 21.11/6.23 21.11/6.23 The TRS R consists of the following rules: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 Q is empty. 21.11/6.23 We have to consider all minimal (P,Q,R)-chains. 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (3) QDPOrderProof (EQUIVALENT) 21.11/6.23 We use the reduction pair processor [LPAR04,JAR06]. 21.11/6.23 21.11/6.23 21.11/6.23 The following pairs can be oriented strictly and are deleted. 21.11/6.23 21.11/6.23 A(b(b(x1))) -> A(x1) 21.11/6.23 The remaining pairs can at least be oriented weakly. 21.11/6.23 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(A(x_1)) = [[-I]] + [[0A, 0A, 0A]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(b(x_1)) = [[-I], [-I], [0A]] + [[0A, -I, -I], [0A, -I, 0A], [0A, 1A, -I]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(a(x_1)) = [[-I], [0A], [-I]] + [[0A, -I, 0A], [1A, 0A, 1A], [0A, -I, 0A]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 21.11/6.23 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (4) 21.11/6.23 Obligation: 21.11/6.23 Q DP problem: 21.11/6.23 The TRS P consists of the following rules: 21.11/6.23 21.11/6.23 A(b(b(x1))) -> A(a(x1)) 21.11/6.23 21.11/6.23 The TRS R consists of the following rules: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 Q is empty. 21.11/6.23 We have to consider all minimal (P,Q,R)-chains. 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (5) QDPOrderProof (EQUIVALENT) 21.11/6.23 We use the reduction pair processor [LPAR04,JAR06]. 21.11/6.23 21.11/6.23 21.11/6.23 The following pairs can be oriented strictly and are deleted. 21.11/6.23 21.11/6.23 A(b(b(x1))) -> A(a(x1)) 21.11/6.23 The remaining pairs can at least be oriented weakly. 21.11/6.23 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(A(x_1)) = [[-I]] + [[0A, -I, -I]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(b(x_1)) = [[0A], [-I], [-I]] + [[-I, 1A, 0A], [0A, -I, -I], [-I, -I, 0A]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 <<< 21.11/6.23 POL(a(x_1)) = [[-I], [0A], [0A]] + [[0A, -I, -I], [1A, 0A, 0A], [0A, -I, -I]] * x_1 21.11/6.23 >>> 21.11/6.23 21.11/6.23 21.11/6.23 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (6) 21.11/6.23 Obligation: 21.11/6.23 Q DP problem: 21.11/6.23 P is empty. 21.11/6.23 The TRS R consists of the following rules: 21.11/6.23 21.11/6.23 a(b(a(x1))) -> b(b(b(b(x1)))) 21.11/6.23 a(b(b(x1))) -> b(b(a(a(x1)))) 21.11/6.23 21.11/6.23 Q is empty. 21.11/6.23 We have to consider all minimal (P,Q,R)-chains. 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (7) PisEmptyProof (EQUIVALENT) 21.11/6.23 The TRS P is empty. Hence, there is no (P,Q,R) chain. 21.11/6.23 ---------------------------------------- 21.11/6.23 21.11/6.23 (8) 21.11/6.23 YES 21.24/6.29 EOF