2.02/0.81	YES
2.02/0.81	
2.02/0.81	Problem:
2.02/0.81	 a(b(x1)) -> b(b(b(b(x1))))
2.02/0.81	 b(a(x1)) -> a(a(a(a(x1))))
2.02/0.81	 a(x1) -> x1
2.02/0.81	 b(x1) -> x1
2.02/0.81	
2.02/0.81	Proof:
2.02/0.81	 String Reversal Processor:
2.02/0.81	  b(a(x1)) -> b(b(b(b(x1))))
2.02/0.81	  a(b(x1)) -> a(a(a(a(x1))))
2.02/0.81	  a(x1) -> x1
2.02/0.81	  b(x1) -> x1
2.02/0.81	  Bounds Processor:
2.02/0.81	   bound: 0
2.02/0.81	   enrichment: match
2.02/0.81	   automaton:
2.02/0.81	    final states: {2,6,1}
2.02/0.81	    transitions:
2.02/0.81	     f20() -> 2*
2.02/0.81	     b0(5) -> 1*
2.02/0.81	     b0(2) -> 3*
2.02/0.81	     b0(4) -> 5*
2.02/0.81	     b0(3) -> 4*
2.02/0.81	     a0(7) -> 8*
2.02/0.81	     a0(2) -> 7*
2.02/0.81	     a0(9) -> 6*
2.02/0.81	     a0(8) -> 9*
2.02/0.81	     1 -> 3,4
2.02/0.81	     2 -> 3,7
2.02/0.81	     3 -> 4*
2.02/0.81	     4 -> 5*
2.02/0.81	     5 -> 1*
2.02/0.81	     6 -> 7,8
2.02/0.81	     7 -> 8*
2.02/0.81	     8 -> 9*
2.02/0.81	     9 -> 6*
2.02/0.81	   problem:
2.02/0.81	    
2.02/0.81	   Qed
2.02/0.81	EOF