18.33/5.03	YES
18.33/5.04	
18.33/5.04	Problem:
18.33/5.04	 a(a(b(b(b(b(a(a(x1)))))))) -> a(a(c(c(a(a(b(b(x1))))))))
18.33/5.04	 a(a(c(c(x1)))) -> c(c(c(c(a(a(x1))))))
18.33/5.04	 c(c(c(c(c(c(x1)))))) -> b(b(c(c(b(b(x1))))))
18.33/5.04	
18.33/5.04	Proof:
18.33/5.04	 String Reversal Processor:
18.33/5.04	  a(a(b(b(b(b(a(a(x1)))))))) -> b(b(a(a(c(c(a(a(x1))))))))
18.33/5.04	  c(c(a(a(x1)))) -> a(a(c(c(c(c(x1))))))
18.33/5.04	  c(c(c(c(c(c(x1)))))) -> b(b(c(c(b(b(x1))))))
18.33/5.04	  Matrix Interpretation Processor: dim=4
18.33/5.04	   
18.33/5.04	   interpretation:
18.33/5.04	              [1 0 0 0]  
18.33/5.04	              [0 1 0 0]  
18.33/5.04	    [c](x0) = [0 0 0 0]x0
18.33/5.04	              [0 1 0 0]  ,
18.33/5.04	    
18.33/5.04	              [1 0 0 0]  
18.33/5.04	              [0 0 0 0]  
18.33/5.04	    [b](x0) = [0 0 0 1]x0
18.33/5.04	              [0 0 0 1]  ,
18.33/5.04	    
18.33/5.04	              [1 0 1 0]     [0]
18.33/5.04	              [0 0 0 1]     [0]
18.33/5.04	    [a](x0) = [0 0 1 0]x0 + [0]
18.33/5.04	              [0 0 0 0]     [1]
18.33/5.04	   orientation:
18.33/5.04	                                 [1 0 2 0]     [2]    [1 0 2 0]     [0]                             
18.33/5.04	                                 [0 0 0 0]     [1]    [0 0 0 0]     [0]                             
18.33/5.04	    a(a(b(b(b(b(a(a(x1)))))))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(b(a(a(c(c(a(a(x1))))))))
18.33/5.04	                                 [0 0 0 0]     [1]    [0 0 0 0]     [1]                             
18.33/5.04	    
18.33/5.04	                     [1 0 2 0]     [0]    [1 0 0 0]     [0]                       
18.33/5.04	                     [0 0 0 0]     [1]    [0 0 0 0]     [1]                       
18.33/5.04	    c(c(a(a(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = a(a(c(c(c(c(x1))))))
18.33/5.04	                     [0 0 0 0]     [1]    [0 0 0 0]     [1]                       
18.33/5.04	    
18.33/5.04	                           [1 0 0 0]      [1 0 0 0]                         
18.33/5.04	                           [0 1 0 0]      [0 0 0 0]                         
18.33/5.04	    c(c(c(c(c(c(x1)))))) = [0 0 0 0]x1 >= [0 0 0 0]x1 = b(b(c(c(b(b(x1))))))
18.33/5.04	                           [0 1 0 0]      [0 0 0 0]                         
18.33/5.04	   problem:
18.33/5.04	    c(c(a(a(x1)))) -> a(a(c(c(c(c(x1))))))
18.33/5.04	    c(c(c(c(c(c(x1)))))) -> b(b(c(c(b(b(x1))))))
18.33/5.04	   String Reversal Processor:
18.33/5.04	    a(a(c(c(x1)))) -> c(c(c(c(a(a(x1))))))
18.33/5.04	    c(c(c(c(c(c(x1)))))) -> b(b(c(c(b(b(x1))))))
18.33/5.04	    Bounds Processor:
18.33/5.04	     bound: 1
18.33/5.04	     enrichment: match
18.33/5.04	     automaton:
18.33/5.04	      final states: {8,1}
18.33/5.04	      transitions:
18.33/5.04	       f30() -> 2*
18.33/5.04	       c0(10) -> 11*
18.33/5.04	       c0(5) -> 6*
18.33/5.04	       c0(7) -> 1*
18.33/5.04	       c0(4) -> 5*
18.33/5.04	       c0(11) -> 12*
18.33/5.04	       c0(6) -> 7*
18.33/5.04	       a0(2) -> 3*
18.33/5.04	       a0(3) -> 4*
18.33/5.04	       b0(12) -> 13*
18.33/5.04	       b0(2) -> 9*
18.33/5.04	       b0(9) -> 10*
18.33/5.04	       b0(13) -> 8*
18.33/5.04	       b1(40) -> 41*
18.33/5.04	       b1(35) -> 36*
18.33/5.04	       b1(15) -> 16*
18.33/5.04	       b1(67) -> 68*
18.33/5.04	       b1(47) -> 48*
18.33/5.04	       b1(42) -> 43*
18.33/5.04	       b1(64) -> 65*
18.33/5.04	       b1(39) -> 40*
18.33/5.04	       b1(19) -> 20*
18.33/5.04	       b1(14) -> 15*
18.33/5.04	       b1(46) -> 47*
18.33/5.04	       b1(36) -> 37*
18.33/5.04	       b1(68) -> 69*
18.33/5.04	       b1(63) -> 64*
18.33/5.04	       b1(43) -> 44*
18.33/5.04	       b1(18) -> 19*
18.33/5.04	       c1(65) -> 66*
18.33/5.04	       c1(45) -> 46*
18.33/5.04	       c1(37) -> 38*
18.33/5.04	       c1(17) -> 18*
18.33/5.04	       c1(44) -> 45*
18.33/5.04	       c1(66) -> 67*
18.33/5.04	       c1(16) -> 17*
18.33/5.04	       c1(38) -> 39*
18.33/5.04	       1 -> 3,4
18.33/5.04	       4 -> 63*
18.33/5.04	       5 -> 42*
18.33/5.04	       6 -> 14*
18.33/5.04	       7 -> 35*
18.33/5.04	       20 -> 1*
18.33/5.04	       41 -> 5*
18.33/5.04	       48 -> 7*
18.33/5.04	       69 -> 6*
18.33/5.04	     problem:
18.48/5.04	      
18.48/5.04	     Qed
18.48/5.05	EOF