10.46/3.09	YES
10.92/3.10	
10.92/3.10	Problem:
10.92/3.10	 b(b(a(b(x1)))) -> b(a(b(b(x1))))
10.92/3.10	 b(a(b(b(x1)))) -> b(b(b(b(x1))))
10.92/3.10	 a(b(b(a(x1)))) -> b(a(a(a(x1))))
10.92/3.10	 b(a(b(a(x1)))) -> a(a(a(a(x1))))
10.92/3.10	
10.92/3.10	Proof:
10.92/3.10	 String Reversal Processor:
10.92/3.10	  b(a(b(b(x1)))) -> b(b(a(b(x1))))
10.92/3.10	  b(b(a(b(x1)))) -> b(b(b(b(x1))))
10.92/3.10	  a(b(b(a(x1)))) -> a(a(a(b(x1))))
10.92/3.10	  a(b(a(b(x1)))) -> a(a(a(a(x1))))
10.92/3.10	  Matrix Interpretation Processor: dim=4
10.92/3.10	   
10.92/3.10	   interpretation:
10.92/3.10	              [1 1 0 0]     [0]
10.92/3.10	              [0 0 1 0]     [0]
10.92/3.10	    [a](x0) = [0 0 0 0]x0 + [1]
10.92/3.10	              [0 1 0 1]     [0],
10.92/3.10	    
10.92/3.10	              [1 0 0 0]     [0]
10.92/3.10	              [0 1 1 1]     [0]
10.92/3.10	    [b](x0) = [0 0 0 0]x0 + [1]
10.92/3.10	              [0 0 0 0]     [0]
10.92/3.10	   orientation:
10.92/3.10	                     [1 1 1 1]     [1]    [1 1 1 1]     [0]                 
10.92/3.10	                     [0 1 1 1]     [3]    [0 1 1 1]     [3]                 
10.92/3.10	    b(a(b(b(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(b(a(b(x1))))
10.92/3.10	                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
10.92/3.10	    
10.92/3.10	                     [1 1 1 1]     [0]    [1 0 0 0]     [0]                 
10.92/3.10	                     [0 1 1 1]     [3]    [0 1 1 1]     [3]                 
10.92/3.10	    b(b(a(b(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = b(b(b(b(x1))))
10.92/3.10	                     [0 0 0 0]     [0]    [0 0 0 0]     [0]                 
10.92/3.10	    
10.92/3.10	                     [1 2 1 1]     [2]    [1 1 1 1]     [2]                 
10.92/3.10	                     [0 0 0 0]     [1]    [0 0 0 0]     [1]                 
10.92/3.10	    a(b(b(a(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(a(b(x1))))
10.92/3.10	                     [0 1 1 1]     [2]    [0 1 1 1]     [2]                 
10.92/3.10	    
10.92/3.10	                     [1 2 2 2]     [2]    [1 1 1 0]     [2]                 
10.92/3.10	                     [0 0 0 0]     [1]    [0 0 0 0]     [1]                 
10.92/3.10	    a(b(a(b(x1)))) = [0 0 0 0]x1 + [1] >= [0 0 0 0]x1 + [1] = a(a(a(a(x1))))
10.92/3.10	                     [0 1 1 1]     [2]    [0 1 1 1]     [2]                 
10.92/3.10	   problem:
10.92/3.10	    b(b(a(b(x1)))) -> b(b(b(b(x1))))
10.92/3.10	    a(b(b(a(x1)))) -> a(a(a(b(x1))))
10.92/3.10	    a(b(a(b(x1)))) -> a(a(a(a(x1))))
10.92/3.10	   String Reversal Processor:
10.92/3.10	    b(a(b(b(x1)))) -> b(b(b(b(x1))))
10.92/3.10	    a(b(b(a(x1)))) -> b(a(a(a(x1))))
10.92/3.10	    b(a(b(a(x1)))) -> a(a(a(a(x1))))
10.92/3.10	    Bounds Processor:
10.92/3.10	     bound: 0
10.92/3.10	     enrichment: match
10.92/3.10	     automaton:
10.92/3.10	      final states: {10,6,1}
10.92/3.10	      transitions:
10.92/3.10	       f20() -> 2*
10.92/3.10	       b0(5) -> 1*
10.92/3.10	       b0(2) -> 3*
10.92/3.10	       b0(9) -> 6*
10.92/3.10	       b0(4) -> 5*
10.92/3.10	       b0(3) -> 4*
10.92/3.10	       a0(7) -> 8*
10.92/3.10	       a0(2) -> 7*
10.92/3.10	       a0(9) -> 10*
10.92/3.10	       a0(8) -> 9*
10.92/3.10	       1 -> 3*
10.92/3.10	       6 -> 7*
10.92/3.10	       10 -> 3*
10.92/3.10	     problem:
10.92/3.10	      
10.92/3.10	     Qed
10.92/3.10	EOF