19.77/5.50	YES
19.77/5.51	
19.77/5.51	Problem:
19.77/5.51	 a(b(a(a(x1)))) -> a(b(b(a(x1))))
19.77/5.51	 a(b(a(b(x1)))) -> a(b(b(a(x1))))
19.77/5.51	 b(b(a(a(x1)))) -> a(b(a(a(x1))))
19.77/5.51	 b(b(b(b(x1)))) -> a(a(a(a(x1))))
19.77/5.51	
19.77/5.51	Proof:
19.77/5.51	 Matrix Interpretation Processor: dim=3
19.77/5.51	  
19.77/5.51	  interpretation:
19.77/5.51	             [1 1 0]     [0]
19.77/5.51	   [b](x0) = [0 0 1]x0 + [0]
19.77/5.51	             [1 0 0]     [1],
19.77/5.51	   
19.77/5.51	             [1 0 0]  
19.77/5.51	   [a](x0) = [0 0 0]x0
19.77/5.51	             [0 0 0]  
19.77/5.51	  orientation:
19.77/5.51	                    [1 0 0]      [1 0 0]                   
19.77/5.51	   a(b(a(a(x1)))) = [0 0 0]x1 >= [0 0 0]x1 = a(b(b(a(x1))))
19.77/5.51	                    [0 0 0]      [0 0 0]                   
19.77/5.51	   
19.77/5.51	                    [1 1 0]      [1 0 0]                   
19.77/5.51	   a(b(a(b(x1)))) = [0 0 0]x1 >= [0 0 0]x1 = a(b(b(a(x1))))
19.77/5.51	                    [0 0 0]      [0 0 0]                   
19.77/5.51	   
19.77/5.51	                    [1 0 0]     [0]    [1 0 0]                   
19.77/5.51	   b(b(a(a(x1)))) = [1 0 0]x1 + [1] >= [0 0 0]x1 = a(b(a(a(x1))))
19.77/5.51	                    [1 0 0]     [1]    [0 0 0]                   
19.77/5.51	   
19.77/5.51	                    [3 2 1]     [2]    [1 0 0]                   
19.77/5.51	   b(b(b(b(x1)))) = [1 1 1]x1 + [1] >= [0 0 0]x1 = a(a(a(a(x1))))
19.77/5.51	                    [2 1 1]     [2]    [0 0 0]                   
19.77/5.51	  problem:
19.77/5.51	   a(b(a(a(x1)))) -> a(b(b(a(x1))))
19.77/5.51	   a(b(a(b(x1)))) -> a(b(b(a(x1))))
19.77/5.51	   b(b(a(a(x1)))) -> a(b(a(a(x1))))
19.77/5.51	  Matrix Interpretation Processor: dim=3
19.77/5.51	   
19.77/5.51	   interpretation:
19.77/5.51	              [1 0 1]     [1]
19.77/5.51	    [b](x0) = [0 0 2]x0 + [0]
19.77/5.51	              [0 2 0]     [0],
19.77/5.51	    
19.77/5.51	              [1 0 0]     [1]
19.77/5.51	    [a](x0) = [0 0 0]x0 + [0]
19.77/5.51	              [1 0 0]     [0]
19.77/5.51	   orientation:
19.77/5.51	                     [2 0 0]     [5]    [2 0 0]     [4]                 
19.77/5.51	    a(b(a(a(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(b(a(x1))))
19.77/5.51	                     [2 0 0]     [4]    [2 0 0]     [3]                 
19.77/5.51	    
19.77/5.51	                     [2 0 2]     [5]    [2 0 0]     [4]                 
19.77/5.51	    a(b(a(b(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(b(a(x1))))
19.77/5.51	                     [2 0 2]     [4]    [2 0 0]     [3]                 
19.77/5.51	    
19.77/5.51	                     [2 0 0]     [5]    [2 0 0]     [5]                 
19.77/5.51	    b(b(a(a(x1)))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = a(b(a(a(x1))))
19.77/5.51	                     [4 0 0]     [4]    [2 0 0]     [4]                 
19.77/5.51	   problem:
19.77/5.51	    b(b(a(a(x1)))) -> a(b(a(a(x1))))
19.77/5.51	   String Reversal Processor:
19.77/5.51	    a(a(b(b(x1)))) -> a(a(b(a(x1))))
19.77/5.51	    KBO Processor:
19.77/5.51	     weight function:
19.77/5.51	      w0 = 1
19.77/5.51	      w(b) = w(a) = 1
19.77/5.51	     precedence:
19.77/5.51	      b > a
19.77/5.51	     problem:
19.77/5.51	      
19.77/5.51	     Qed
20.36/5.51	EOF