15.43/4.81 YES 15.79/4.83 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 15.79/4.83 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 15.79/4.83 15.79/4.83 15.79/4.83 Termination w.r.t. Q of the given QTRS could be proven: 15.79/4.83 15.79/4.83 (0) QTRS 15.79/4.83 (1) FlatCCProof [EQUIVALENT, 0 ms] 15.79/4.83 (2) QTRS 15.79/4.83 (3) RootLabelingProof [EQUIVALENT, 0 ms] 15.79/4.83 (4) QTRS 15.79/4.83 (5) QTRSRRRProof [EQUIVALENT, 34 ms] 15.79/4.83 (6) QTRS 15.79/4.83 (7) DependencyPairsProof [EQUIVALENT, 0 ms] 15.79/4.83 (8) QDP 15.79/4.83 (9) DependencyGraphProof [EQUIVALENT, 0 ms] 15.79/4.83 (10) QDP 15.79/4.83 (11) QDPOrderProof [EQUIVALENT, 23 ms] 15.79/4.83 (12) QDP 15.79/4.83 (13) DependencyGraphProof [EQUIVALENT, 0 ms] 15.79/4.83 (14) TRUE 15.79/4.83 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (0) 15.79/4.83 Obligation: 15.79/4.83 Q restricted rewrite system: 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a(a(a(a(x1)))) -> a(b(b(b(x1)))) 15.79/4.83 a(b(b(b(x1)))) -> b(a(b(a(x1)))) 15.79/4.83 b(a(a(b(x1)))) -> b(a(b(b(x1)))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (1) FlatCCProof (EQUIVALENT) 15.79/4.83 We used flat context closure [ROOTLAB] 15.79/4.83 As Q is empty the flat context closure was sound AND complete. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (2) 15.79/4.83 Obligation: 15.79/4.83 Q restricted rewrite system: 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a(a(a(a(x1)))) -> a(b(b(b(x1)))) 15.79/4.83 b(a(a(b(x1)))) -> b(a(b(b(x1)))) 15.79/4.83 a(a(b(b(b(x1))))) -> a(b(a(b(a(x1))))) 15.79/4.83 b(a(b(b(b(x1))))) -> b(b(a(b(a(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (3) RootLabelingProof (EQUIVALENT) 15.79/4.83 We used plain root labeling [ROOTLAB] with the following heuristic: 15.79/4.83 LabelAll: All function symbols get labeled 15.79/4.83 15.79/4.83 As Q is empty the root labeling was sound AND complete. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (4) 15.79/4.83 Obligation: 15.79/4.83 Q restricted rewrite system: 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1))))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (5) QTRSRRRProof (EQUIVALENT) 15.79/4.83 Used ordering: 15.79/4.83 Polynomial interpretation [POLO]: 15.79/4.83 15.79/4.83 POL(a_{a_1}(x_1)) = 1 + x_1 15.79/4.83 POL(a_{b_1}(x_1)) = x_1 15.79/4.83 POL(b_{a_1}(x_1)) = 1 + x_1 15.79/4.83 POL(b_{b_1}(x_1)) = 1 + x_1 15.79/4.83 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 a_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1))))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1))))) 15.79/4.83 15.79/4.83 15.79/4.83 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (6) 15.79/4.83 Obligation: 15.79/4.83 Q restricted rewrite system: 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (7) DependencyPairsProof (EQUIVALENT) 15.79/4.83 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (8) 15.79/4.83 Obligation: 15.79/4.83 Q DP problem: 15.79/4.83 The TRS P consists of the following rules: 15.79/4.83 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{a_1}(x1)) 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> A_{A_1}(x1) 15.79/4.83 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 We have to consider all minimal (P,Q,R)-chains. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (9) DependencyGraphProof (EQUIVALENT) 15.79/4.83 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 1 less node. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (10) 15.79/4.83 Obligation: 15.79/4.83 Q DP problem: 15.79/4.83 The TRS P consists of the following rules: 15.79/4.83 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{a_1}(x1)) 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 We have to consider all minimal (P,Q,R)-chains. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (11) QDPOrderProof (EQUIVALENT) 15.79/4.83 We use the reduction pair processor [LPAR04,JAR06]. 15.79/4.83 15.79/4.83 15.79/4.83 The following pairs can be oriented strictly and are deleted. 15.79/4.83 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> B_{A_1}(a_{a_1}(x1)) 15.79/4.83 The remaining pairs can at least be oriented weakly. 15.79/4.83 Used ordering: Polynomial interpretation [POLO]: 15.79/4.83 15.79/4.83 POL(B_{A_1}(x_1)) = x_1 15.79/4.83 POL(a_{a_1}(x_1)) = 1 + x_1 15.79/4.83 POL(a_{b_1}(x_1)) = 1 + x_1 15.79/4.83 POL(b_{a_1}(x_1)) = 1 + x_1 15.79/4.83 POL(b_{b_1}(x_1)) = 1 + x_1 15.79/4.83 15.79/4.83 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 15.79/4.83 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (12) 15.79/4.83 Obligation: 15.79/4.83 Q DP problem: 15.79/4.83 The TRS P consists of the following rules: 15.79/4.83 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 B_{A_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 15.79/4.83 The TRS R consists of the following rules: 15.79/4.83 15.79/4.83 a_{a_1}(a_{a_1}(a_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) 15.79/4.83 b_{a_1}(a_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) 15.79/4.83 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1))))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1))))) 15.79/4.83 15.79/4.83 Q is empty. 15.79/4.83 We have to consider all minimal (P,Q,R)-chains. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (13) DependencyGraphProof (EQUIVALENT) 15.79/4.83 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 2 less nodes. 15.79/4.83 ---------------------------------------- 15.79/4.83 15.79/4.83 (14) 15.79/4.83 TRUE 15.96/4.97 EOF