5.81/1.81 YES 5.81/1.82 5.81/1.82 Problem: 5.81/1.82 b(b(b(b(x1)))) -> b(b(a(a(x1)))) 5.81/1.82 b(b(a(a(x1)))) -> a(b(a(b(x1)))) 5.81/1.82 a(b(a(a(x1)))) -> a(b(a(b(x1)))) 5.81/1.82 5.81/1.82 Proof: 5.81/1.82 String Reversal Processor: 5.81/1.82 b(b(b(b(x1)))) -> a(a(b(b(x1)))) 5.81/1.82 a(a(b(b(x1)))) -> b(a(b(a(x1)))) 5.81/1.82 a(a(b(a(x1)))) -> b(a(b(a(x1)))) 5.81/1.82 Matrix Interpretation Processor: dim=4 5.81/1.82 5.81/1.82 interpretation: 5.81/1.82 [1 0 0 0] 5.81/1.82 [0 0 1 0] 5.81/1.82 [a](x0) = [0 1 0 0]x0 5.81/1.82 [0 0 0 0] , 5.81/1.82 5.81/1.82 [1 0 0 1] [0] 5.81/1.82 [0 0 0 0] [1] 5.81/1.82 [b](x0) = [0 0 0 0]x0 + [0] 5.81/1.82 [0 1 0 0] [0] 5.81/1.82 orientation: 5.81/1.82 [1 1 0 1] [2] [1 1 0 1] [0] 5.81/1.82 [0 0 0 0] [1] [0 0 0 0] [1] 5.81/1.82 b(b(b(b(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = a(a(b(b(x1)))) 5.81/1.82 [0 0 0 0] [1] [0 0 0 0] [0] 5.81/1.82 5.81/1.82 [1 1 0 1] [0] [1 0 0 0] [0] 5.81/1.82 [0 0 0 0] [1] [0 0 0 0] [1] 5.81/1.82 a(a(b(b(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = b(a(b(a(x1)))) 5.81/1.82 [0 0 0 0] [0] [0 0 0 0] [0] 5.81/1.82 5.81/1.82 [1 0 0 0] [0] [1 0 0 0] [0] 5.81/1.82 [0 0 0 0] [1] [0 0 0 0] [1] 5.81/1.82 a(a(b(a(x1)))) = [0 0 0 0]x1 + [0] >= [0 0 0 0]x1 + [0] = b(a(b(a(x1)))) 5.81/1.82 [0 0 0 0] [0] [0 0 0 0] [0] 5.81/1.82 problem: 5.81/1.82 a(a(b(b(x1)))) -> b(a(b(a(x1)))) 5.81/1.82 a(a(b(a(x1)))) -> b(a(b(a(x1)))) 5.81/1.82 KBO Processor: 5.81/1.82 weight function: 5.81/1.82 w0 = 1 5.81/1.82 w(a) = w(b) = 1 5.81/1.82 precedence: 5.81/1.82 a > b 5.81/1.82 problem: 5.81/1.82 5.81/1.82 Qed 5.81/1.82 EOF