12.75/4.10 YES 12.75/4.15 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 12.75/4.15 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 12.75/4.15 12.75/4.15 12.75/4.15 Termination w.r.t. Q of the given QTRS could be proven: 12.75/4.15 12.75/4.15 (0) QTRS 12.75/4.15 (1) RootLabelingProof [EQUIVALENT, 0 ms] 12.75/4.15 (2) QTRS 12.75/4.15 (3) QTRSRRRProof [EQUIVALENT, 8 ms] 12.75/4.15 (4) QTRS 12.75/4.15 (5) DependencyPairsProof [EQUIVALENT, 0 ms] 12.75/4.15 (6) QDP 12.75/4.15 (7) DependencyGraphProof [EQUIVALENT, 1 ms] 12.75/4.15 (8) AND 12.75/4.15 (9) QDP 12.75/4.15 (10) UsableRulesProof [EQUIVALENT, 0 ms] 12.75/4.15 (11) QDP 12.75/4.15 (12) QDPOrderProof [EQUIVALENT, 6 ms] 12.75/4.15 (13) QDP 12.75/4.15 (14) PisEmptyProof [EQUIVALENT, 0 ms] 12.75/4.15 (15) YES 12.75/4.15 (16) QDP 12.75/4.15 (17) QDPSizeChangeProof [EQUIVALENT, 0 ms] 12.75/4.15 (18) YES 12.75/4.15 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (0) 12.75/4.15 Obligation: 12.75/4.15 Q restricted rewrite system: 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a(a(b(a(x1)))) -> a(b(a(a(x1)))) 12.75/4.15 b(a(b(b(x1)))) -> b(b(a(b(x1)))) 12.75/4.15 a(b(a(b(x1)))) -> a(b(b(b(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (1) RootLabelingProof (EQUIVALENT) 12.75/4.15 We used plain root labeling [ROOTLAB] with the following heuristic: 12.75/4.15 LabelAll: All function symbols get labeled 12.75/4.15 12.75/4.15 As Q is empty the root labeling was sound AND complete. 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (2) 12.75/4.15 Obligation: 12.75/4.15 Q restricted rewrite system: 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))) 12.75/4.15 a_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (3) QTRSRRRProof (EQUIVALENT) 12.75/4.15 Used ordering: 12.75/4.15 Polynomial interpretation [POLO]: 12.75/4.15 12.75/4.15 POL(a_{a_1}(x_1)) = x_1 12.75/4.15 POL(a_{b_1}(x_1)) = x_1 12.75/4.15 POL(b_{a_1}(x_1)) = 1 + x_1 12.75/4.15 POL(b_{b_1}(x_1)) = x_1 12.75/4.15 With this ordering the following rules can be removed by the rule removal processor [LPAR04] because they are oriented strictly: 12.75/4.15 12.75/4.15 a_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{a_1}(x1)))) 12.75/4.15 a_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) -> a_{b_1}(b_{b_1}(b_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 12.75/4.15 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (4) 12.75/4.15 Obligation: 12.75/4.15 Q restricted rewrite system: 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (5) DependencyPairsProof (EQUIVALENT) 12.75/4.15 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (6) 12.75/4.15 Obligation: 12.75/4.15 Q DP problem: 12.75/4.15 The TRS P consists of the following rules: 12.75/4.15 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> B_{A_1}(a_{a_1}(a_{a_1}(x1))) 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> A_{A_1}(a_{a_1}(x1)) 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> B_{A_1}(a_{a_1}(a_{b_1}(x1))) 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> A_{A_1}(a_{b_1}(x1)) 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{a_1}(x1))) 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(x1))) 12.75/4.15 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 We have to consider all minimal (P,Q,R)-chains. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (7) DependencyGraphProof (EQUIVALENT) 12.75/4.15 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 2 less nodes. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (8) 12.75/4.15 Complex Obligation (AND) 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (9) 12.75/4.15 Obligation: 12.75/4.15 Q DP problem: 12.75/4.15 The TRS P consists of the following rules: 12.75/4.15 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(x1))) 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{a_1}(x1))) 12.75/4.15 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 We have to consider all minimal (P,Q,R)-chains. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (10) UsableRulesProof (EQUIVALENT) 12.75/4.15 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (11) 12.75/4.15 Obligation: 12.75/4.15 Q DP problem: 12.75/4.15 The TRS P consists of the following rules: 12.75/4.15 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(x1))) 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{a_1}(x1))) 12.75/4.15 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 We have to consider all minimal (P,Q,R)-chains. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (12) QDPOrderProof (EQUIVALENT) 12.75/4.15 We use the reduction pair processor [LPAR04,JAR06]. 12.75/4.15 12.75/4.15 12.75/4.15 The following pairs can be oriented strictly and are deleted. 12.75/4.15 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{b_1}(x1))) 12.75/4.15 B_{A_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> B_{A_1}(a_{b_1}(b_{a_1}(x1))) 12.75/4.15 The remaining pairs can at least be oriented weakly. 12.75/4.15 Used ordering: Polynomial interpretation [POLO]: 12.75/4.15 12.75/4.15 POL(B_{A_1}(x_1)) = x_1 12.75/4.15 POL(a_{b_1}(x_1)) = x_1 12.75/4.15 POL(b_{a_1}(x_1)) = 1 + x_1 12.75/4.15 POL(b_{b_1}(x_1)) = 1 + x_1 12.75/4.15 12.75/4.15 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 12.75/4.15 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (13) 12.75/4.15 Obligation: 12.75/4.15 Q DP problem: 12.75/4.15 P is empty. 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 We have to consider all minimal (P,Q,R)-chains. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (14) PisEmptyProof (EQUIVALENT) 12.75/4.15 The TRS P is empty. Hence, there is no (P,Q,R) chain. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (15) 12.75/4.15 YES 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (16) 12.75/4.15 Obligation: 12.75/4.15 Q DP problem: 12.75/4.15 The TRS P consists of the following rules: 12.75/4.15 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> A_{A_1}(a_{b_1}(x1)) 12.75/4.15 A_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> A_{A_1}(a_{a_1}(x1)) 12.75/4.15 12.75/4.15 The TRS R consists of the following rules: 12.75/4.15 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{a_1}(x1)))) 12.75/4.15 a_{a_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> a_{b_1}(b_{a_1}(a_{a_1}(a_{b_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{a_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{a_1}(x1)))) 12.75/4.15 b_{a_1}(a_{b_1}(b_{b_1}(b_{b_1}(x1)))) -> b_{b_1}(b_{a_1}(a_{b_1}(b_{b_1}(x1)))) 12.75/4.15 12.75/4.15 Q is empty. 12.75/4.15 We have to consider all minimal (P,Q,R)-chains. 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (17) QDPSizeChangeProof (EQUIVALENT) 12.75/4.15 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 12.75/4.15 12.75/4.15 From the DPs we obtained the following set of size-change graphs: 12.75/4.15 *A_{A_1}(a_{b_1}(b_{a_1}(a_{b_1}(x1)))) -> A_{A_1}(a_{b_1}(x1)) 12.75/4.15 The graph contains the following edges 1 > 1 12.75/4.15 12.75/4.15 12.75/4.15 *A_{A_1}(a_{b_1}(b_{a_1}(a_{a_1}(x1)))) -> A_{A_1}(a_{a_1}(x1)) 12.75/4.15 The graph contains the following edges 1 > 1 12.75/4.15 12.75/4.15 12.75/4.15 ---------------------------------------- 12.75/4.15 12.75/4.15 (18) 12.75/4.15 YES 13.09/4.23 EOF