162.18/42.18 YES 162.55/42.25 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 162.55/42.25 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 162.55/42.25 162.55/42.25 162.55/42.25 Termination w.r.t. Q of the given QTRS could be proven: 162.55/42.25 162.55/42.25 (0) QTRS 162.55/42.25 (1) DependencyPairsProof [EQUIVALENT, 32 ms] 162.55/42.25 (2) QDP 162.55/42.25 (3) DependencyGraphProof [EQUIVALENT, 1 ms] 162.55/42.25 (4) AND 162.55/42.25 (5) QDP 162.55/42.25 (6) UsableRulesProof [EQUIVALENT, 0 ms] 162.55/42.25 (7) QDP 162.55/42.25 (8) QDPSizeChangeProof [EQUIVALENT, 1 ms] 162.55/42.25 (9) YES 162.55/42.25 (10) QDP 162.55/42.25 (11) QDPOrderProof [EQUIVALENT, 30 ms] 162.55/42.25 (12) QDP 162.55/42.25 (13) QDPOrderProof [EQUIVALENT, 2671 ms] 162.55/42.25 (14) QDP 162.55/42.25 (15) QDPOrderProof [EQUIVALENT, 3127 ms] 162.55/42.25 (16) QDP 162.55/42.25 (17) PisEmptyProof [EQUIVALENT, 0 ms] 162.55/42.25 (18) YES 162.55/42.25 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (0) 162.55/42.25 Obligation: 162.55/42.25 Q restricted rewrite system: 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (1) DependencyPairsProof (EQUIVALENT) 162.55/42.25 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (2) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(a(x1))) 162.55/42.25 A(a(b(b(x1)))) -> A(a(x1)) 162.55/42.25 A(a(b(b(x1)))) -> A(x1) 162.55/42.25 A(c(x1)) -> C(a(x1)) 162.55/42.25 A(c(x1)) -> A(x1) 162.55/42.25 C(b(x1)) -> C(x1) 162.55/42.25 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (3) DependencyGraphProof (EQUIVALENT) 162.55/42.25 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 1 less node. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (4) 162.55/42.25 Complex Obligation (AND) 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (5) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 C(b(x1)) -> C(x1) 162.55/42.25 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (6) UsableRulesProof (EQUIVALENT) 162.55/42.25 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (7) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 C(b(x1)) -> C(x1) 162.55/42.25 162.55/42.25 R is empty. 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (8) QDPSizeChangeProof (EQUIVALENT) 162.55/42.25 By using the subterm criterion [SUBTERM_CRITERION] together with the size-change analysis [AAECC05] we have proven that there are no infinite chains for this DP problem. 162.55/42.25 162.55/42.25 From the DPs we obtained the following set of size-change graphs: 162.55/42.25 *C(b(x1)) -> C(x1) 162.55/42.25 The graph contains the following edges 1 > 1 162.55/42.25 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (9) 162.55/42.25 YES 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (10) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(x1)) 162.55/42.25 A(a(b(b(x1)))) -> A(a(a(x1))) 162.55/42.25 A(a(b(b(x1)))) -> A(x1) 162.55/42.25 A(c(x1)) -> A(x1) 162.55/42.25 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (11) QDPOrderProof (EQUIVALENT) 162.55/42.25 We use the reduction pair processor [LPAR04,JAR06]. 162.55/42.25 162.55/42.25 162.55/42.25 The following pairs can be oriented strictly and are deleted. 162.55/42.25 162.55/42.25 A(c(x1)) -> A(x1) 162.55/42.25 The remaining pairs can at least be oriented weakly. 162.55/42.25 Used ordering: Polynomial interpretation [POLO]: 162.55/42.25 162.55/42.25 POL(A(x_1)) = x_1 162.55/42.25 POL(a(x_1)) = x_1 162.55/42.25 POL(b(x_1)) = x_1 162.55/42.25 POL(c(x_1)) = 1 + x_1 162.55/42.25 162.55/42.25 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (12) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(x1)) 162.55/42.25 A(a(b(b(x1)))) -> A(a(a(x1))) 162.55/42.25 A(a(b(b(x1)))) -> A(x1) 162.55/42.25 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (13) QDPOrderProof (EQUIVALENT) 162.55/42.25 We use the reduction pair processor [LPAR04,JAR06]. 162.55/42.25 162.55/42.25 162.55/42.25 The following pairs can be oriented strictly and are deleted. 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(a(x1))) 162.55/42.25 A(a(b(b(x1)))) -> A(x1) 162.55/42.25 The remaining pairs can at least be oriented weakly. 162.55/42.25 Used ordering: Matrix interpretation [MATRO] with arctic natural numbers [ARCTIC]: 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(A(x_1)) = [[0A]] + [[0A, -I, -I]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(a(x_1)) = [[0A], [0A], [0A]] + [[-I, -I, 0A], [1A, -I, 0A], [0A, -I, -I]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(b(x_1)) = [[0A], [0A], [1A]] + [[-I, -I, -I], [1A, -I, 0A], [0A, 0A, -I]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(c(x_1)) = [[-I], [-I], [0A]] + [[0A, -I, -I], [0A, 0A, -I], [-I, -I, 0A]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 162.55/42.25 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (14) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 The TRS P consists of the following rules: 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(x1)) 162.55/42.25 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (15) QDPOrderProof (EQUIVALENT) 162.55/42.25 We use the reduction pair processor [LPAR04,JAR06]. 162.55/42.25 162.55/42.25 162.55/42.25 The following pairs can be oriented strictly and are deleted. 162.55/42.25 162.55/42.25 A(a(b(b(x1)))) -> A(a(x1)) 162.55/42.25 The remaining pairs can at least be oriented weakly. 162.55/42.25 Used ordering: Matrix interpretation [MATRO] to (N^5, +, *, >=, >) : 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(A(x_1)) = [[0]] + [[0, 1, 1, 0, 0]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(a(x_1)) = [[0], [0], [0], [0], [0]] + [[0, 1, 0, 0, 0], [1, 0, 0, 0, 0], [1, 0, 0, 0, 0], [0, 1, 1, 0, 0], [0, 0, 0, 0, 0]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(b(x_1)) = [[0], [0], [0], [1], [0]] + [[0, 0, 0, 1, 1], [0, 0, 0, 0, 0], [0, 0, 0, 0, 0], [1, 1, 0, 0, 0], [0, 1, 0, 0, 0]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 <<< 162.55/42.25 POL(c(x_1)) = [[0], [0], [0], [0], [0]] + [[1, 0, 0, 0, 0], [0, 1, 0, 0, 0], [0, 0, 1, 0, 0], [0, 0, 0, 1, 0], [0, 0, 0, 0, 1]] * x_1 162.55/42.25 >>> 162.55/42.25 162.55/42.25 162.55/42.25 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (16) 162.55/42.25 Obligation: 162.55/42.25 Q DP problem: 162.55/42.25 P is empty. 162.55/42.25 The TRS R consists of the following rules: 162.55/42.25 162.55/42.25 a(a(b(b(x1)))) -> b(b(b(a(a(a(x1)))))) 162.55/42.25 a(c(x1)) -> c(a(x1)) 162.55/42.25 c(b(x1)) -> b(c(x1)) 162.55/42.25 162.55/42.25 Q is empty. 162.55/42.25 We have to consider all minimal (P,Q,R)-chains. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (17) PisEmptyProof (EQUIVALENT) 162.55/42.25 The TRS P is empty. Hence, there is no (P,Q,R) chain. 162.55/42.25 ---------------------------------------- 162.55/42.25 162.55/42.25 (18) 162.55/42.25 YES 162.75/42.34 EOF