11.29/3.31	YES
11.79/3.32	
11.79/3.32	Problem:
11.79/3.32	 1(2(1(x1))) -> 2(0(2(x1)))
11.79/3.32	 0(2(1(x1))) -> 1(0(2(x1)))
11.79/3.32	 L(2(1(x1))) -> L(1(0(2(x1))))
11.79/3.32	 1(2(0(x1))) -> 2(0(1(x1)))
11.79/3.32	 1(2(R(x1))) -> 2(0(1(R(x1))))
11.79/3.32	 0(2(0(x1))) -> 1(0(1(x1)))
11.79/3.32	 L(2(0(x1))) -> L(1(0(1(x1))))
11.79/3.32	 0(2(R(x1))) -> 1(0(1(R(x1))))
11.79/3.32	
11.79/3.32	Proof:
11.79/3.32	 Matrix Interpretation Processor: dim=3
11.79/3.32	  
11.79/3.32	  interpretation:
11.79/3.32	             [1 0 0]     [0]
11.79/3.32	   [R](x0) = [0 0 0]x0 + [0]
11.79/3.32	             [0 0 0]     [1],
11.79/3.32	   
11.79/3.32	             [1 0 1]  
11.79/3.32	   [L](x0) = [0 0 0]x0
11.79/3.32	             [0 0 0]  ,
11.79/3.32	   
11.79/3.32	             [1 0 0]  
11.79/3.32	   [0](x0) = [0 0 0]x0
11.79/3.32	             [0 0 0]  ,
11.79/3.32	   
11.79/3.32	             [1 0 0]     [0]
11.79/3.32	   [2](x0) = [0 0 0]x0 + [0]
11.79/3.32	             [0 0 0]     [1],
11.79/3.32	   
11.79/3.32	             [1 0 0]  
11.79/3.32	   [1](x0) = [0 0 0]x0
11.79/3.32	             [0 0 1]  
11.79/3.32	  orientation:
11.79/3.32	                 [1 0 0]     [0]    [1 0 0]     [0]              
11.79/3.32	   1(2(1(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = 2(0(2(x1)))
11.79/3.32	                 [0 0 0]     [1]    [0 0 0]     [1]              
11.79/3.32	   
11.79/3.32	                 [1 0 0]      [1 0 0]                
11.79/3.32	   0(2(1(x1))) = [0 0 0]x1 >= [0 0 0]x1 = 1(0(2(x1)))
11.79/3.32	                 [0 0 0]      [0 0 0]                
11.79/3.32	   
11.79/3.32	                 [1 0 0]     [1]    [1 0 0]                   
11.79/3.32	   L(2(1(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 = L(1(0(2(x1))))
11.79/3.32	                 [0 0 0]     [0]    [0 0 0]                   
11.79/3.32	   
11.79/3.32	                 [1 0 0]     [0]    [1 0 0]     [0]              
11.79/3.32	   1(2(0(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = 2(0(1(x1)))
11.79/3.32	                 [0 0 0]     [1]    [0 0 0]     [1]              
11.79/3.32	   
11.79/3.32	                 [1 0 0]     [0]    [1 0 0]     [0]                 
11.79/3.32	   1(2(R(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 + [0] = 2(0(1(R(x1))))
11.79/3.32	                 [0 0 0]     [1]    [0 0 0]     [1]                 
11.79/3.32	   
11.79/3.32	                 [1 0 0]      [1 0 0]                
11.79/3.32	   0(2(0(x1))) = [0 0 0]x1 >= [0 0 0]x1 = 1(0(1(x1)))
11.79/3.32	                 [0 0 0]      [0 0 0]                
11.79/3.32	   
11.79/3.32	                 [1 0 0]     [1]    [1 0 0]                   
11.79/3.32	   L(2(0(x1))) = [0 0 0]x1 + [0] >= [0 0 0]x1 = L(1(0(1(x1))))
11.79/3.32	                 [0 0 0]     [0]    [0 0 0]                   
11.79/3.32	   
11.79/3.32	                 [1 0 0]      [1 0 0]                   
11.79/3.32	   0(2(R(x1))) = [0 0 0]x1 >= [0 0 0]x1 = 1(0(1(R(x1))))
11.79/3.32	                 [0 0 0]      [0 0 0]                   
11.79/3.32	  problem:
11.79/3.32	   1(2(1(x1))) -> 2(0(2(x1)))
11.79/3.32	   0(2(1(x1))) -> 1(0(2(x1)))
11.79/3.32	   1(2(0(x1))) -> 2(0(1(x1)))
11.79/3.32	   1(2(R(x1))) -> 2(0(1(R(x1))))
11.79/3.32	   0(2(0(x1))) -> 1(0(1(x1)))
11.79/3.32	   0(2(R(x1))) -> 1(0(1(R(x1))))
11.79/3.32	  String Reversal Processor:
11.79/3.32	   1(2(1(x1))) -> 2(0(2(x1)))
11.79/3.32	   1(2(0(x1))) -> 2(0(1(x1)))
11.79/3.32	   0(2(1(x1))) -> 1(0(2(x1)))
11.79/3.32	   R(2(1(x1))) -> R(1(0(2(x1))))
11.79/3.32	   0(2(0(x1))) -> 1(0(1(x1)))
11.79/3.32	   R(2(0(x1))) -> R(1(0(1(x1))))
11.79/3.32	   Matrix Interpretation Processor: dim=1
11.79/3.32	    
11.79/3.32	    interpretation:
11.79/3.32	     [R](x0) = 2x0,
11.79/3.32	     
11.79/3.32	     [0](x0) = x0 + 3,
11.79/3.32	     
11.79/3.32	     [2](x0) = 4x0,
11.79/3.32	     
11.79/3.32	     [1](x0) = 2x0 + 2
11.79/3.32	    orientation:
11.79/3.32	     1(2(1(x1))) = 16x1 + 18 >= 16x1 + 12 = 2(0(2(x1)))
11.79/3.32	     
11.79/3.32	     1(2(0(x1))) = 8x1 + 26 >= 8x1 + 20 = 2(0(1(x1)))
11.79/3.32	     
11.79/3.32	     0(2(1(x1))) = 8x1 + 11 >= 8x1 + 8 = 1(0(2(x1)))
11.79/3.32	     
11.79/3.32	     R(2(1(x1))) = 16x1 + 16 >= 16x1 + 16 = R(1(0(2(x1))))
11.79/3.32	     
11.79/3.32	     0(2(0(x1))) = 4x1 + 15 >= 4x1 + 12 = 1(0(1(x1)))
11.79/3.32	     
11.79/3.32	     R(2(0(x1))) = 8x1 + 24 >= 8x1 + 24 = R(1(0(1(x1))))
11.79/3.32	    problem:
11.79/3.32	     R(2(1(x1))) -> R(1(0(2(x1))))
11.79/3.32	     R(2(0(x1))) -> R(1(0(1(x1))))
11.79/3.32	    String Reversal Processor:
11.79/3.32	     1(2(R(x1))) -> 2(0(1(R(x1))))
11.79/3.32	     0(2(R(x1))) -> 1(0(1(R(x1))))
11.79/3.32	     Bounds Processor:
11.79/3.32	      bound: 0
11.79/3.32	      enrichment: match
11.79/3.32	      automaton:
11.79/3.32	       final states: {6,1}
11.79/3.32	       transitions:
11.79/3.32	        f50() -> 2*
11.79/3.32	        20(5) -> 1*
11.79/3.32	        00(4) -> 5*
11.79/3.32	        10(5) -> 6*
11.79/3.32	        10(3) -> 4*
11.79/3.32	        R0(2) -> 3*
11.79/3.32	      problem:
11.79/3.32	       
11.79/3.32	      Qed
11.79/3.33	EOF