28.52/8.23 YES 29.05/8.33 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 29.05/8.33 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 29.05/8.33 29.05/8.33 29.05/8.33 Termination w.r.t. Q of the given QTRS could be proven: 29.05/8.33 29.05/8.33 (0) QTRS 29.05/8.33 (1) QTRS Reverse [EQUIVALENT, 0 ms] 29.05/8.33 (2) QTRS 29.05/8.33 (3) DependencyPairsProof [EQUIVALENT, 26 ms] 29.05/8.33 (4) QDP 29.05/8.33 (5) DependencyGraphProof [EQUIVALENT, 0 ms] 29.05/8.33 (6) AND 29.05/8.33 (7) QDP 29.05/8.33 (8) UsableRulesProof [EQUIVALENT, 0 ms] 29.05/8.33 (9) QDP 29.05/8.33 (10) QDPOrderProof [EQUIVALENT, 109 ms] 29.05/8.33 (11) QDP 29.05/8.33 (12) DependencyGraphProof [EQUIVALENT, 0 ms] 29.05/8.33 (13) AND 29.05/8.33 (14) QDP 29.05/8.33 (15) QDPOrderProof [EQUIVALENT, 0 ms] 29.05/8.33 (16) QDP 29.05/8.33 (17) PisEmptyProof [EQUIVALENT, 0 ms] 29.05/8.33 (18) YES 29.05/8.33 (19) QDP 29.05/8.33 (20) QDPOrderProof [EQUIVALENT, 25 ms] 29.05/8.33 (21) QDP 29.05/8.33 (22) DependencyGraphProof [EQUIVALENT, 0 ms] 29.05/8.33 (23) TRUE 29.05/8.33 (24) QDP 29.05/8.33 (25) UsableRulesProof [EQUIVALENT, 4 ms] 29.05/8.33 (26) QDP 29.05/8.33 (27) QDPOrderProof [EQUIVALENT, 12 ms] 29.05/8.33 (28) QDP 29.05/8.33 (29) MRRProof [EQUIVALENT, 3 ms] 29.05/8.33 (30) QDP 29.05/8.33 (31) PisEmptyProof [EQUIVALENT, 0 ms] 29.05/8.33 (32) YES 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (0) 29.05/8.33 Obligation: 29.05/8.33 Q restricted rewrite system: 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(s(x1)) -> s(a(x1)) 29.05/8.33 b(a(b(s(x1)))) -> a(b(s(a(x1)))) 29.05/8.33 b(a(b(b(x1)))) -> c(s(x1)) 29.05/8.33 c(s(x1)) -> a(b(a(b(x1)))) 29.05/8.33 a(b(a(a(x1)))) -> b(a(b(a(x1)))) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (1) QTRS Reverse (EQUIVALENT) 29.05/8.33 We applied the QTRS Reverse Processor [REVERSE]. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (2) 29.05/8.33 Obligation: 29.05/8.33 Q restricted rewrite system: 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 s(a(x1)) -> a(s(x1)) 29.05/8.33 s(b(a(b(x1)))) -> a(s(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (3) DependencyPairsProof (EQUIVALENT) 29.05/8.33 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (4) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(a(x1)) -> A(s(x1)) 29.05/8.33 S(a(x1)) -> S(x1) 29.05/8.33 S(b(a(b(x1)))) -> A(s(b(a(x1)))) 29.05/8.33 S(b(a(b(x1)))) -> S(b(a(x1))) 29.05/8.33 S(b(a(b(x1)))) -> B(a(x1)) 29.05/8.33 S(b(a(b(x1)))) -> A(x1) 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 S(c(x1)) -> A(b(a(x1))) 29.05/8.33 S(c(x1)) -> B(a(x1)) 29.05/8.33 S(c(x1)) -> A(x1) 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 A(a(b(a(x1)))) -> B(a(b(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(x1)) 29.05/8.33 A(a(b(a(x1)))) -> B(x1) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 s(a(x1)) -> a(s(x1)) 29.05/8.33 s(b(a(b(x1)))) -> a(s(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (5) DependencyGraphProof (EQUIVALENT) 29.05/8.33 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs with 4 less nodes. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (6) 29.05/8.33 Complex Obligation (AND) 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (7) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 S(c(x1)) -> A(b(a(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 A(a(b(a(x1)))) -> B(a(b(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(x1)) 29.05/8.33 A(a(b(a(x1)))) -> B(x1) 29.05/8.33 S(c(x1)) -> B(a(x1)) 29.05/8.33 S(c(x1)) -> A(x1) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 s(a(x1)) -> a(s(x1)) 29.05/8.33 s(b(a(b(x1)))) -> a(s(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (8) UsableRulesProof (EQUIVALENT) 29.05/8.33 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (9) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 S(c(x1)) -> A(b(a(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 A(a(b(a(x1)))) -> B(a(b(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(x1)) 29.05/8.33 A(a(b(a(x1)))) -> B(x1) 29.05/8.33 S(c(x1)) -> B(a(x1)) 29.05/8.33 S(c(x1)) -> A(x1) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (10) QDPOrderProof (EQUIVALENT) 29.05/8.33 We use the reduction pair processor [LPAR04,JAR06]. 29.05/8.33 29.05/8.33 29.05/8.33 The following pairs can be oriented strictly and are deleted. 29.05/8.33 29.05/8.33 S(c(x1)) -> A(b(a(x1))) 29.05/8.33 A(a(b(a(x1)))) -> B(a(b(x1))) 29.05/8.33 A(a(b(a(x1)))) -> A(b(x1)) 29.05/8.33 A(a(b(a(x1)))) -> B(x1) 29.05/8.33 S(c(x1)) -> B(a(x1)) 29.05/8.33 S(c(x1)) -> A(x1) 29.05/8.33 The remaining pairs can at least be oriented weakly. 29.05/8.33 Used ordering: Polynomial interpretation [POLO]: 29.05/8.33 29.05/8.33 POL(A(x_1)) = 2*x_1 29.05/8.33 POL(B(x_1)) = 2*x_1 29.05/8.33 POL(S(x_1)) = 4 + 2*x_1 29.05/8.33 POL(a(x_1)) = 1 + x_1 29.05/8.33 POL(b(x_1)) = 1 + x_1 29.05/8.33 POL(c(x_1)) = 1 + x_1 29.05/8.33 POL(s(x_1)) = 3 + x_1 29.05/8.33 29.05/8.33 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (11) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (12) DependencyGraphProof (EQUIVALENT) 29.05/8.33 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 2 SCCs. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (13) 29.05/8.33 Complex Obligation (AND) 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (14) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (15) QDPOrderProof (EQUIVALENT) 29.05/8.33 We use the reduction pair processor [LPAR04,JAR06]. 29.05/8.33 29.05/8.33 29.05/8.33 The following pairs can be oriented strictly and are deleted. 29.05/8.33 29.05/8.33 A(a(b(a(x1)))) -> A(b(a(b(x1)))) 29.05/8.33 The remaining pairs can at least be oriented weakly. 29.05/8.33 Used ordering: Polynomial interpretation [POLO]: 29.05/8.33 29.05/8.33 POL(A(x_1)) = x_1 29.05/8.33 POL(a(x_1)) = 1 29.05/8.33 POL(b(x_1)) = 0 29.05/8.33 POL(c(x_1)) = 0 29.05/8.33 POL(s(x_1)) = x_1 29.05/8.33 29.05/8.33 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 29.05/8.33 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (16) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 P is empty. 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (17) PisEmptyProof (EQUIVALENT) 29.05/8.33 The TRS P is empty. Hence, there is no (P,Q,R) chain. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (18) 29.05/8.33 YES 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (19) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (20) QDPOrderProof (EQUIVALENT) 29.05/8.33 We use the reduction pair processor [LPAR04,JAR06]. 29.05/8.33 29.05/8.33 29.05/8.33 The following pairs can be oriented strictly and are deleted. 29.05/8.33 29.05/8.33 S(c(x1)) -> B(a(b(a(x1)))) 29.05/8.33 The remaining pairs can at least be oriented weakly. 29.05/8.33 Used ordering: Polynomial Order [NEGPOLO,POLO] with Interpretation: 29.05/8.33 29.05/8.33 POL( B_1(x_1) ) = x_1 + 2 29.05/8.33 POL( a_1(x_1) ) = 0 29.05/8.33 POL( b_1(x_1) ) = 1 29.05/8.33 POL( s_1(x_1) ) = 2x_1 29.05/8.33 POL( c_1(x_1) ) = 2 29.05/8.33 POL( S_1(x_1) ) = max{0, 2x_1 - 1} 29.05/8.33 29.05/8.33 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (21) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 B(b(a(b(x1)))) -> S(c(x1)) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (22) DependencyGraphProof (EQUIVALENT) 29.05/8.33 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 0 SCCs with 1 less node. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (23) 29.05/8.33 TRUE 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (24) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(b(a(b(x1)))) -> S(b(a(x1))) 29.05/8.33 S(a(x1)) -> S(x1) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 s(a(x1)) -> a(s(x1)) 29.05/8.33 s(b(a(b(x1)))) -> a(s(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (25) UsableRulesProof (EQUIVALENT) 29.05/8.33 We can use the usable rules and reduction pair processor [LPAR04] with the Ce-compatible extension of the polynomial order that maps every function symbol to the sum of its arguments. Then, we can delete all non-usable rules [FROCOS05] from R. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (26) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(b(a(b(x1)))) -> S(b(a(x1))) 29.05/8.33 S(a(x1)) -> S(x1) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (27) QDPOrderProof (EQUIVALENT) 29.05/8.33 We use the reduction pair processor [LPAR04,JAR06]. 29.05/8.33 29.05/8.33 29.05/8.33 The following pairs can be oriented strictly and are deleted. 29.05/8.33 29.05/8.33 S(a(x1)) -> S(x1) 29.05/8.33 The remaining pairs can at least be oriented weakly. 29.05/8.33 Used ordering: Polynomial interpretation [POLO]: 29.05/8.33 29.05/8.33 POL(S(x_1)) = x_1 29.05/8.33 POL(a(x_1)) = 1 + x_1 29.05/8.33 POL(b(x_1)) = 1 29.05/8.33 POL(c(x_1)) = 1 29.05/8.33 POL(s(x_1)) = x_1 29.05/8.33 29.05/8.33 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 29.05/8.33 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (28) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 The TRS P consists of the following rules: 29.05/8.33 29.05/8.33 S(b(a(b(x1)))) -> S(b(a(x1))) 29.05/8.33 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (29) MRRProof (EQUIVALENT) 29.05/8.33 By using the rule removal processor [LPAR04] with the following ordering, at least one Dependency Pair or term rewrite system rule of this QDP problem can be strictly oriented. 29.05/8.33 29.05/8.33 Strictly oriented dependency pairs: 29.05/8.33 29.05/8.33 S(b(a(b(x1)))) -> S(b(a(x1))) 29.05/8.33 29.05/8.33 29.05/8.33 Used ordering: Polynomial interpretation [POLO]: 29.05/8.33 29.05/8.33 POL(S(x_1)) = 2*x_1 29.05/8.33 POL(a(x_1)) = 1 + x_1 29.05/8.33 POL(b(x_1)) = 1 + x_1 29.05/8.33 POL(c(x_1)) = 1 + x_1 29.05/8.33 POL(s(x_1)) = 3 + x_1 29.05/8.33 29.05/8.33 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (30) 29.05/8.33 Obligation: 29.05/8.33 Q DP problem: 29.05/8.33 P is empty. 29.05/8.33 The TRS R consists of the following rules: 29.05/8.33 29.05/8.33 a(a(b(a(x1)))) -> a(b(a(b(x1)))) 29.05/8.33 s(c(x1)) -> b(a(b(a(x1)))) 29.05/8.33 b(b(a(b(x1)))) -> s(c(x1)) 29.05/8.33 29.05/8.33 Q is empty. 29.05/8.33 We have to consider all minimal (P,Q,R)-chains. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (31) PisEmptyProof (EQUIVALENT) 29.05/8.33 The TRS P is empty. Hence, there is no (P,Q,R) chain. 29.05/8.33 ---------------------------------------- 29.05/8.33 29.05/8.33 (32) 29.05/8.33 YES 29.19/8.42 EOF