39.94/11.09 YES 40.61/11.26 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 40.61/11.26 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 40.61/11.26 40.61/11.26 40.61/11.26 Termination w.r.t. Q of the given QTRS could be proven: 40.61/11.26 40.61/11.26 (0) QTRS 40.61/11.26 (1) DependencyPairsProof [EQUIVALENT, 4 ms] 40.61/11.26 (2) QDP 40.61/11.26 (3) QDPOrderProof [EQUIVALENT, 34 ms] 40.61/11.26 (4) QDP 40.61/11.26 (5) DependencyGraphProof [EQUIVALENT, 1 ms] 40.61/11.26 (6) QDP 40.61/11.26 (7) QDPOrderProof [EQUIVALENT, 38 ms] 40.61/11.26 (8) QDP 40.61/11.26 (9) PisEmptyProof [EQUIVALENT, 0 ms] 40.61/11.26 (10) YES 40.61/11.26 40.61/11.26 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (0) 40.61/11.26 Obligation: 40.61/11.26 Q restricted rewrite system: 40.61/11.26 The TRS R consists of the following rules: 40.61/11.26 40.61/11.26 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.26 c(a(x1)) -> a(c(x1)) 40.61/11.26 c(b(x1)) -> b(a(x1)) 40.61/11.26 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.26 a(d(x1)) -> d(a(x1)) 40.61/11.26 b(d(x1)) -> a(b(x1)) 40.61/11.26 a(a(x1)) -> a(b(a(x1))) 40.61/11.26 40.61/11.26 Q is empty. 40.61/11.26 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (1) DependencyPairsProof (EQUIVALENT) 40.61/11.26 Using Dependency Pairs [AG00,LPAR04] we result in the following initial DP problem. 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (2) 40.61/11.26 Obligation: 40.61/11.26 Q DP problem: 40.61/11.26 The TRS P consists of the following rules: 40.61/11.26 40.61/11.26 B(a(a(x1))) -> A(b(c(x1))) 40.61/11.26 B(a(a(x1))) -> B(c(x1)) 40.61/11.26 B(a(a(x1))) -> C(x1) 40.61/11.26 C(a(x1)) -> A(c(x1)) 40.61/11.26 C(a(x1)) -> C(x1) 40.61/11.26 C(b(x1)) -> B(a(x1)) 40.61/11.26 C(b(x1)) -> A(x1) 40.61/11.26 A(a(b(x1))) -> B(a(x1)) 40.61/11.26 A(a(b(x1))) -> A(x1) 40.61/11.26 A(d(x1)) -> A(x1) 40.61/11.26 B(d(x1)) -> A(b(x1)) 40.61/11.26 B(d(x1)) -> B(x1) 40.61/11.26 A(a(x1)) -> A(b(a(x1))) 40.61/11.26 A(a(x1)) -> B(a(x1)) 40.61/11.26 40.61/11.26 The TRS R consists of the following rules: 40.61/11.26 40.61/11.26 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.26 c(a(x1)) -> a(c(x1)) 40.61/11.26 c(b(x1)) -> b(a(x1)) 40.61/11.26 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.26 a(d(x1)) -> d(a(x1)) 40.61/11.26 b(d(x1)) -> a(b(x1)) 40.61/11.26 a(a(x1)) -> a(b(a(x1))) 40.61/11.26 40.61/11.26 Q is empty. 40.61/11.26 We have to consider all minimal (P,Q,R)-chains. 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (3) QDPOrderProof (EQUIVALENT) 40.61/11.26 We use the reduction pair processor [LPAR04,JAR06]. 40.61/11.26 40.61/11.26 40.61/11.26 The following pairs can be oriented strictly and are deleted. 40.61/11.26 40.61/11.26 B(a(a(x1))) -> A(b(c(x1))) 40.61/11.26 B(a(a(x1))) -> B(c(x1)) 40.61/11.26 B(a(a(x1))) -> C(x1) 40.61/11.26 C(a(x1)) -> A(c(x1)) 40.61/11.26 C(a(x1)) -> C(x1) 40.61/11.26 C(b(x1)) -> A(x1) 40.61/11.26 A(a(b(x1))) -> A(x1) 40.61/11.26 A(d(x1)) -> A(x1) 40.61/11.26 B(d(x1)) -> A(b(x1)) 40.61/11.26 B(d(x1)) -> B(x1) 40.61/11.26 The remaining pairs can at least be oriented weakly. 40.61/11.26 Used ordering: Polynomial interpretation [POLO]: 40.61/11.26 40.61/11.26 POL(A(x_1)) = x_1 40.61/11.26 POL(B(x_1)) = x_1 40.61/11.26 POL(C(x_1)) = 1 + x_1 40.61/11.26 POL(a(x_1)) = 1 + x_1 40.61/11.26 POL(b(x_1)) = x_1 40.61/11.26 POL(c(x_1)) = 1 + x_1 40.61/11.26 POL(d(x_1)) = 1 + x_1 40.61/11.26 40.61/11.26 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 40.61/11.26 40.61/11.26 c(a(x1)) -> a(c(x1)) 40.61/11.26 c(b(x1)) -> b(a(x1)) 40.61/11.26 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.26 b(d(x1)) -> a(b(x1)) 40.61/11.26 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.26 a(d(x1)) -> d(a(x1)) 40.61/11.26 a(a(x1)) -> a(b(a(x1))) 40.61/11.26 40.61/11.26 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (4) 40.61/11.26 Obligation: 40.61/11.26 Q DP problem: 40.61/11.26 The TRS P consists of the following rules: 40.61/11.26 40.61/11.26 C(b(x1)) -> B(a(x1)) 40.61/11.26 A(a(b(x1))) -> B(a(x1)) 40.61/11.26 A(a(x1)) -> A(b(a(x1))) 40.61/11.26 A(a(x1)) -> B(a(x1)) 40.61/11.26 40.61/11.26 The TRS R consists of the following rules: 40.61/11.26 40.61/11.26 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.26 c(a(x1)) -> a(c(x1)) 40.61/11.26 c(b(x1)) -> b(a(x1)) 40.61/11.26 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.26 a(d(x1)) -> d(a(x1)) 40.61/11.26 b(d(x1)) -> a(b(x1)) 40.61/11.26 a(a(x1)) -> a(b(a(x1))) 40.61/11.26 40.61/11.26 Q is empty. 40.61/11.26 We have to consider all minimal (P,Q,R)-chains. 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (5) DependencyGraphProof (EQUIVALENT) 40.61/11.26 The approximation of the Dependency Graph [LPAR04,FROCOS05,EDGSTAR] contains 1 SCC with 3 less nodes. 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (6) 40.61/11.26 Obligation: 40.61/11.26 Q DP problem: 40.61/11.26 The TRS P consists of the following rules: 40.61/11.26 40.61/11.26 A(a(x1)) -> A(b(a(x1))) 40.61/11.26 40.61/11.26 The TRS R consists of the following rules: 40.61/11.26 40.61/11.26 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.26 c(a(x1)) -> a(c(x1)) 40.61/11.26 c(b(x1)) -> b(a(x1)) 40.61/11.26 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.26 a(d(x1)) -> d(a(x1)) 40.61/11.26 b(d(x1)) -> a(b(x1)) 40.61/11.26 a(a(x1)) -> a(b(a(x1))) 40.61/11.26 40.61/11.26 Q is empty. 40.61/11.26 We have to consider all minimal (P,Q,R)-chains. 40.61/11.26 ---------------------------------------- 40.61/11.26 40.61/11.26 (7) QDPOrderProof (EQUIVALENT) 40.61/11.26 We use the reduction pair processor [LPAR04,JAR06]. 40.61/11.26 40.61/11.26 40.61/11.26 The following pairs can be oriented strictly and are deleted. 40.61/11.26 40.61/11.26 A(a(x1)) -> A(b(a(x1))) 40.61/11.26 The remaining pairs can at least be oriented weakly. 40.61/11.26 Used ordering: Polynomial interpretation [POLO,RATPOLO]: 40.61/11.27 40.61/11.27 POL(A(x_1)) = [1/4]x_1 40.61/11.27 POL(a(x_1)) = [2] + [2]x_1 40.61/11.27 POL(b(x_1)) = [1/2]x_1 40.61/11.27 POL(c(x_1)) = [1] + [2]x_1 40.61/11.27 POL(d(x_1)) = [4] + [2]x_1 40.61/11.27 The value of delta used in the strict ordering is 1/4. 40.61/11.27 The following usable rules [FROCOS05] with respect to the argument filtering of the ordering [JAR06] were oriented: 40.61/11.27 40.61/11.27 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.27 a(d(x1)) -> d(a(x1)) 40.61/11.27 a(a(x1)) -> a(b(a(x1))) 40.61/11.27 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.27 b(d(x1)) -> a(b(x1)) 40.61/11.27 c(a(x1)) -> a(c(x1)) 40.61/11.27 c(b(x1)) -> b(a(x1)) 40.61/11.27 40.61/11.27 40.61/11.27 ---------------------------------------- 40.61/11.27 40.61/11.27 (8) 40.61/11.27 Obligation: 40.61/11.27 Q DP problem: 40.61/11.27 P is empty. 40.61/11.27 The TRS R consists of the following rules: 40.61/11.27 40.61/11.27 b(a(a(x1))) -> a(b(c(x1))) 40.61/11.27 c(a(x1)) -> a(c(x1)) 40.61/11.27 c(b(x1)) -> b(a(x1)) 40.61/11.27 a(a(b(x1))) -> d(b(a(x1))) 40.61/11.27 a(d(x1)) -> d(a(x1)) 40.61/11.27 b(d(x1)) -> a(b(x1)) 40.61/11.27 a(a(x1)) -> a(b(a(x1))) 40.61/11.27 40.61/11.27 Q is empty. 40.61/11.27 We have to consider all minimal (P,Q,R)-chains. 40.61/11.27 ---------------------------------------- 40.61/11.27 40.61/11.27 (9) PisEmptyProof (EQUIVALENT) 40.61/11.27 The TRS P is empty. Hence, there is no (P,Q,R) chain. 40.61/11.27 ---------------------------------------- 40.61/11.27 40.61/11.27 (10) 40.61/11.27 YES 40.61/11.32 EOF