915.37/299.51 MAYBE 915.37/299.51 915.37/299.51 Problem: 915.37/299.51 strict: 915.37/299.51 1(4(x1)) -> 3(1(1(2(2(4(x1)))))) 915.37/299.51 5(4(x1)) -> 4(2(3(1(1(1(x1)))))) 915.37/299.51 0(3(0(x1))) -> 2(1(1(0(2(0(x1)))))) 915.37/299.51 0(5(5(x1))) -> 1(0(1(3(4(2(x1)))))) 915.37/299.51 1(5(4(x1))) -> 0(2(5(2(0(4(x1)))))) 915.37/299.51 3(5(4(x1))) -> 4(1(3(4(2(3(x1)))))) 915.37/299.51 4(1(4(x1))) -> 3(3(2(2(3(1(x1)))))) 915.37/299.51 5(4(0(x1))) -> 2(4(0(4(4(0(x1)))))) 915.37/299.51 5(4(0(x1))) -> 5(1(5(2(1(0(x1)))))) 915.37/299.51 5(4(4(x1))) -> 4(1(1(3(2(4(x1)))))) 915.37/299.51 5(5(4(x1))) -> 3(4(4(1(2(2(x1)))))) 915.37/299.51 0(5(5(0(x1)))) -> 0(2(0(0(3(0(x1)))))) 915.37/299.51 0(5(5(4(x1)))) -> 0(1(3(4(3(4(x1)))))) 915.37/299.51 1(4(5(4(x1)))) -> 0(4(5(0(2(1(x1)))))) 915.37/299.51 1(4(5(5(x1)))) -> 0(0(1(3(4(1(x1)))))) 915.37/299.51 2(5(4(0(x1)))) -> 0(4(1(2(4(0(x1)))))) 915.37/299.51 4(3(0(5(x1)))) -> 3(3(2(3(5(5(x1)))))) 915.37/299.51 5(4(0(0(x1)))) -> 1(0(4(0(2(2(x1)))))) 915.37/299.51 5(4(0(2(x1)))) -> 3(0(4(5(0(2(x1)))))) 915.37/299.51 weak: 915.37/299.51 0(0(x1)) -> 1(2(1(0(2(0(x1)))))) 915.37/299.51 0(3(x1)) -> 1(2(1(2(0(3(x1)))))) 915.37/299.51 0(1(3(x1))) -> 1(0(3(1(0(4(x1)))))) 915.37/299.51 0(1(5(x1))) -> 0(2(0(3(4(1(x1)))))) 915.37/299.51 0(3(0(x1))) -> 0(2(0(0(5(0(x1)))))) 915.37/299.51 0(5(1(x1))) -> 0(0(0(0(5(1(x1)))))) 915.37/299.51 1(5(4(x1))) -> 0(3(4(3(3(3(x1)))))) 915.37/299.51 2(0(5(x1))) -> 0(3(2(5(1(1(x1)))))) 915.37/299.51 3(0(2(x1))) -> 3(4(2(1(0(2(x1)))))) 915.37/299.51 3(3(0(x1))) -> 3(4(2(3(3(0(x1)))))) 915.37/299.51 0(0(5(0(x1)))) -> 1(0(3(5(3(0(x1)))))) 915.37/299.51 0(1(4(0(x1)))) -> 0(5(0(0(0(3(x1)))))) 915.37/299.51 1(3(3(0(x1)))) -> 1(4(2(2(2(0(x1)))))) 915.37/299.51 1(4(0(2(x1)))) -> 2(0(3(4(0(2(x1)))))) 915.37/299.51 3(0(5(3(x1)))) -> 3(1(1(5(0(3(x1)))))) 915.37/299.51 3(3(3(0(x1)))) -> 3(3(0(4(1(0(x1)))))) 915.37/299.51 4(0(2(3(x1)))) -> 4(0(3(4(3(2(x1)))))) 915.37/299.51 4(1(4(0(x1)))) -> 2(5(0(3(1(0(x1)))))) 915.37/299.51 4(3(5(5(x1)))) -> 3(3(5(3(2(5(x1)))))) 915.37/299.51 4(5(4(0(x1)))) -> 2(5(1(0(5(2(x1)))))) 915.37/299.51 5(4(5(5(x1)))) -> 0(1(0(4(3(1(x1)))))) 915.37/299.51 915.37/299.51 Proof: 915.37/299.51 Open 915.37/299.52 EOF