1.00/1.02	MAYBE
1.00/1.02	Input TRS:
1.00/1.02	    1: 4(2(4(x1))) -> 2(0(0(5(3(3(5(2(0(4(x1))))))))))
1.00/1.02	    2: 4(4(2(4(2(x1))))) -> 2(0(5(2(1(4(0(2(0(1(x1))))))))))
1.00/1.02	    3: 0(5(4(2(4(3(x1)))))) -> 5(1(5(5(3(5(3(0(0(0(x1))))))))))
1.00/1.02	    4: 1(1(4(5(3(3(x1)))))) -> 1(3(1(1(3(0(1(2(2(1(x1))))))))))
1.00/1.02	    5: 3(1(4(3(1(2(x1)))))) -> 0(0(1(1(4(2(3(0(0(3(x1))))))))))
1.00/1.02	    6: 3(2(4(2(4(1(x1)))))) -> 0(2(1(1(1(5(3(1(3(3(x1))))))))))
1.00/1.02	    7: 3(3(0(4(1(2(x1)))))) -> 3(5(1(2(0(2(0(5(3(1(x1))))))))))
1.00/1.02	    8: 4(1(4(5(0(5(4(x1))))))) -> 4(1(5(3(1(0(5(3(1(0(x1))))))))))
1.00/1.02	    9: 4(4(0(5(4(2(2(x1))))))) -> 4(0(4(3(4(4(4(5(4(1(x1))))))))))
1.00/1.02	    10: 5(4(5(3(2(4(3(x1))))))) -> 2(5(5(5(0(4(5(0(1(4(x1))))))))))
1.00/1.02	    11: x1 ->= 0(0(1(0(0(1(0(2(3(1(x1))))))))))
1.00/1.02	    12: x1 ->= 0(1(0(1(0(2(0(4(1(3(x1))))))))))
1.00/1.02	    13: x1 ->= 0(1(0(1(3(5(0(2(2(5(x1))))))))))
1.00/1.02	    14: x1 ->= 1(0(0(0(2(3(3(1(3(3(x1))))))))))
1.00/1.02	    15: x1 ->= 1(5(0(3(2(3(0(3(2(1(x1))))))))))
1.00/1.02	    16: 0(2(x1)) ->= 0(2(0(3(0(1(3(2(2(5(x1))))))))))
1.00/1.02	    17: 1(3(x1)) ->= 1(3(5(0(0(1(0(3(5(2(x1))))))))))
1.00/1.02	    18: 2(2(x1)) ->= 2(2(1(3(1(0(1(2(2(1(x1))))))))))
1.00/1.02	    19: 2(2(x1)) ->= 2(2(1(5(4(5(2(0(1(5(x1))))))))))
1.00/1.02	    20: 2(4(x1)) ->= 2(1(1(3(1(3(4(1(3(1(x1))))))))))
1.00/1.02	    21: 2(4(x1)) ->= 2(5(0(0(1(2(0(3(1(4(x1))))))))))
1.00/1.02	    22: 3(2(x1)) ->= 0(5(0(0(5(2(0(0(5(5(x1))))))))))
1.00/1.02	    23: 4(0(x1)) ->= 0(1(5(0(1(3(1(5(4(2(x1))))))))))
1.00/1.02	    24: 0(0(2(x1))) ->= 0(1(4(5(4(1(0(5(3(0(x1))))))))))
1.00/1.02	    25: 1(2(4(x1))) ->= 0(2(5(0(0(3(2(2(4(4(x1))))))))))
1.00/1.02	    26: 2(2(2(x1))) ->= 2(3(1(0(1(2(0(5(5(0(x1))))))))))
1.00/1.02	    27: 2(4(0(x1))) ->= 1(5(5(0(0(3(3(4(4(0(x1))))))))))
1.00/1.02	    28: 2(5(2(x1))) ->= 2(0(5(0(2(0(3(3(2(1(x1))))))))))
1.00/1.02	    29: 3(1(2(x1))) ->= 3(3(2(0(3(3(3(1(2(0(x1))))))))))
1.00/1.02	    30: 3(3(3(x1))) ->= 3(0(2(1(1(0(3(0(2(3(x1))))))))))
1.00/1.02	    31: 3(3(3(x1))) ->= 3(1(5(5(2(3(3(3(3(1(x1))))))))))
1.00/1.02	    32: 4(0(3(x1))) ->= 4(3(4(5(2(0(0(0(5(1(x1))))))))))
1.00/1.02	    33: 0(2(5(4(x1)))) ->= 1(0(4(3(0(3(5(0(0(5(x1))))))))))
1.00/1.02	    34: 0(3(2(2(x1)))) ->= 0(3(0(5(0(2(1(2(3(1(x1))))))))))
1.00/1.02	    35: 1(1(4(2(x1)))) ->= 3(0(3(4(3(1(5(0(1(5(x1))))))))))
1.00/1.02	    36: 1(2(2(4(x1)))) ->= 3(2(3(0(2(1(0(1(4(4(x1))))))))))
1.00/1.02	    37: 2(2(4(2(x1)))) ->= 2(2(5(5(1(5(0(3(4(2(x1))))))))))
1.00/1.02	    38: 3(3(3(3(x1)))) ->= 1(3(5(2(0(0(3(5(3(0(x1))))))))))
1.00/1.02	    39: 3(4(0(2(x1)))) ->= 3(5(4(0(3(0(1(5(1(0(x1))))))))))
1.00/1.02	    40: 0(2(2(2(4(x1))))) ->= 0(0(2(3(1(1(3(1(0(4(x1))))))))))
1.00/1.02	    41: 0(2(2(2(4(x1))))) ->= 0(2(3(4(1(1(4(5(4(5(x1))))))))))
1.00/1.02	    42: 1(5(3(1(2(x1))))) ->= 1(1(3(0(2(1(3(1(1(0(x1))))))))))
1.00/1.02	    43: 2(3(3(5(4(x1))))) ->= 2(3(2(5(0(2(3(3(3(4(x1))))))))))
1.00/1.02	    44: 2(4(2(0(2(x1))))) ->= 2(3(0(3(3(4(1(2(0(1(x1))))))))))
1.00/1.02	    45: 2(4(3(3(4(x1))))) ->= 2(0(1(4(3(1(2(3(1(2(x1))))))))))
1.00/1.02	    46: 3(0(2(4(2(x1))))) ->= 3(2(5(0(2(0(5(0(1(3(x1))))))))))
1.00/1.02	    47: 3(1(4(2(3(x1))))) ->= 0(3(4(0(4(0(1(0(0(0(x1))))))))))
1.00/1.02	    48: 4(2(4(3(4(x1))))) ->= 1(0(0(5(5(2(4(1(2(2(x1))))))))))
1.00/1.02	    49: 4(4(5(0(3(x1))))) ->= 1(0(5(0(5(1(4(5(0(3(x1))))))))))
1.00/1.02	    50: 0(3(3(5(2(2(x1)))))) ->= 0(0(5(4(2(2(5(2(3(5(x1))))))))))
1.00/1.02	    51: 0(4(2(5(1(2(x1)))))) ->= 0(0(5(1(4(1(2(0(3(3(x1))))))))))
1.00/1.02	    52: 1(4(1(4(3(0(x1)))))) ->= 1(2(3(0(5(1(1(4(4(2(x1))))))))))
1.00/1.02	    53: 2(2(4(3(3(0(x1)))))) ->= 1(0(4(2(1(2(0(1(4(1(x1))))))))))
1.00/1.02	    54: 1(2(2(4(4(3(3(x1))))))) ->= 1(4(3(2(3(4(2(0(0(3(x1))))))))))
1.00/1.02	    55: 2(1(2(4(4(0(3(x1))))))) ->= 2(3(5(4(4(3(2(0(3(1(x1))))))))))
1.00/1.02	    56: 2(2(2(4(2(1(2(x1))))))) ->= 1(5(0(5(5(4(1(2(3(3(x1))))))))))
1.00/1.02	    57: 2(2(4(4(2(2(4(x1))))))) ->= 2(2(5(2(3(4(2(2(4(4(x1))))))))))
1.00/1.02	    58: 2(3(1(5(4(0(5(x1))))))) ->= 0(5(1(0(3(3(4(1(4(3(x1))))))))))
1.00/1.02	    59: 4(4(5(4(3(5(5(x1))))))) ->= 5(2(1(0(1(4(5(3(5(5(x1))))))))))
1.00/1.02	    60: 5(1(2(4(1(3(4(x1))))))) ->= 2(2(0(0(0(1(1(3(1(4(x1))))))))))
1.00/1.02	Number of strict rules: 10
1.00/1.02	Direct POLO(bPol) ... failed.
1.00/1.02	Uncurrying ... failed.
1.00/1.02	weak variable left-hand side
1.00/1.02	EOF