0.00/0.33	YES
0.00/0.35	
0.00/0.35	
0.00/0.35	The system was inverted.
0.00/0.35	
0.00/0.35	Remains to prove termination of the 6-rule system
0.00/0.35	{ a a a -> c b b ,
0.00/0.35	  a a a -> a c a ,
0.00/0.35	  c c b -> c a b ,
0.00/0.35	  b c a ->= c b a ,
0.00/0.35	  a c c ->= a b c ,
0.00/0.35	  a b a ->= b a a }
0.00/0.35	
0.00/0.35	
0.00/0.35	
0.00/0.35	
0.00/0.35	The system was filtered by the following matrix interpretation
0.00/0.35	of type E_J with J = {1,...,2} and dimension 2:
0.00/0.35	
0.00/0.35	c is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 0 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	b is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 1 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	a is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 0 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	
0.00/0.35	Remains to prove termination of the 4-rule system
0.00/0.35	{ a c a -> a a a ,
0.00/0.35	  c a b -> c c b ,
0.00/0.35	  c b a ->= b c a ,
0.00/0.35	  b a a ->= a b a }
0.00/0.35	
0.00/0.35	
0.00/0.35	The system was filtered by the following matrix interpretation
0.00/0.35	of type E_J with J = {1,...,2} and dimension 4:
0.00/0.35	
0.00/0.35	c is interpreted by
0.00/0.35	 /       \
0.00/0.35	| 1 0 0 0 |
0.00/0.35	| 0 1 0 0 |
0.00/0.35	| 0 0 0 1 |
0.00/0.35	| 0 0 0 0 |
0.00/0.35	 \       /
0.00/0.35	b is interpreted by
0.00/0.35	 /       \
0.00/0.35	| 1 0 0 0 |
0.00/0.35	| 0 1 0 0 |
0.00/0.35	| 0 0 0 0 |
0.00/0.35	| 0 0 0 1 |
0.00/0.35	 \       /
0.00/0.35	a is interpreted by
0.00/0.35	 /       \
0.00/0.35	| 1 0 1 0 |
0.00/0.35	| 0 1 0 0 |
0.00/0.35	| 0 0 0 0 |
0.00/0.35	| 0 1 0 0 |
0.00/0.35	 \       /
0.00/0.35	
0.00/0.35	Remains to prove termination of the 3-rule system
0.00/0.35	{ c a b -> c c b ,
0.00/0.35	  c b a ->= b c a ,
0.00/0.35	  b a a ->= a b a }
0.00/0.35	
0.00/0.35	
0.00/0.35	The system was filtered by the following matrix interpretation
0.00/0.35	of type E_J with J = {1,...,2} and dimension 2:
0.00/0.35	
0.00/0.35	c is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 0 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	b is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 0 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	a is interpreted by
0.00/0.35	 /   \
0.00/0.35	| 1 1 |
0.00/0.35	| 0 1 |
0.00/0.35	 \   /
0.00/0.35	
0.00/0.35	Remains to prove termination of the 2-rule system
0.00/0.35	{ c b a ->= b c a ,
0.00/0.35	  b a a ->= a b a }
0.00/0.35	
0.00/0.35	
0.00/0.35	The system is trivially terminating.
0.00/0.38	EOF