2.96/1.48 WORST_CASE(NON_POLY, ?) 2.96/1.49 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 2.96/1.49 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.96/1.49 2.96/1.49 2.96/1.49 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.96/1.49 2.96/1.49 (0) CpxTRS 2.96/1.49 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 2.96/1.49 (2) TRS for Loop Detection 2.96/1.49 (3) InfiniteLowerBoundProof [FINISHED, 0 ms] 2.96/1.49 (4) BOUNDS(INF, INF) 2.96/1.49 2.96/1.49 2.96/1.49 ---------------------------------------- 2.96/1.49 2.96/1.49 (0) 2.96/1.49 Obligation: 2.96/1.49 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.96/1.49 2.96/1.49 2.96/1.49 The TRS R consists of the following rules: 2.96/1.49 2.96/1.49 cons(x, cons(y, z)) -> big 2.96/1.49 inf(x) -> cons(x, inf(s(x))) 2.96/1.49 2.96/1.49 S is empty. 2.96/1.49 Rewrite Strategy: FULL 2.96/1.49 ---------------------------------------- 2.96/1.49 2.96/1.49 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 2.96/1.49 Transformed a relative TRS into a decreasing-loop problem. 2.96/1.49 ---------------------------------------- 2.96/1.49 2.96/1.49 (2) 2.96/1.49 Obligation: 2.96/1.49 Analyzing the following TRS for decreasing loops: 2.96/1.49 2.96/1.49 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.96/1.49 2.96/1.49 2.96/1.49 The TRS R consists of the following rules: 2.96/1.49 2.96/1.49 cons(x, cons(y, z)) -> big 2.96/1.49 inf(x) -> cons(x, inf(s(x))) 2.96/1.49 2.96/1.49 S is empty. 2.96/1.49 Rewrite Strategy: FULL 2.96/1.49 ---------------------------------------- 2.96/1.49 2.96/1.49 (3) InfiniteLowerBoundProof (FINISHED) 2.96/1.49 The following loop proves infinite runtime complexity: 2.96/1.49 2.96/1.49 The rewrite sequence 2.96/1.49 2.96/1.49 inf(x) ->^+ cons(x, inf(s(x))) 2.96/1.49 2.96/1.49 gives rise to a decreasing loop by considering the right hand sides subterm at position [1]. 2.96/1.49 2.96/1.49 The pumping substitution is [ ]. 2.96/1.49 2.96/1.49 The result substitution is [x / s(x)]. 2.96/1.49 2.96/1.49 2.96/1.49 2.96/1.49 2.96/1.49 ---------------------------------------- 2.96/1.49 2.96/1.49 (4) 2.96/1.49 BOUNDS(INF, INF) 3.03/1.53 EOF