3.46/1.60 WORST_CASE(NON_POLY, ?) 3.46/1.61 proof of /export/starexec/sandbox2/benchmark/theBenchmark.xml 3.46/1.61 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.46/1.61 3.46/1.61 3.46/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). 3.46/1.61 3.46/1.61 (0) CpxTRS 3.46/1.61 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 3.46/1.61 (2) TRS for Loop Detection 3.46/1.61 (3) DecreasingLoopProof [LOWER BOUND(ID), 0 ms] 3.46/1.61 (4) BEST 3.46/1.61 (5) proven lower bound 3.46/1.61 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 3.46/1.61 (7) BOUNDS(n^1, INF) 3.46/1.61 (8) TRS for Loop Detection 3.46/1.61 (9) DecreasingLoopProof [FINISHED, 0 ms] 3.46/1.61 (10) BOUNDS(EXP, INF) 3.46/1.61 3.46/1.61 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (0) 3.46/1.61 Obligation: 3.46/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). 3.46/1.61 3.46/1.61 3.46/1.61 The TRS R consists of the following rules: 3.46/1.61 3.46/1.61 a__from(X) -> cons(mark(X), from(s(X))) 3.46/1.61 a__length(nil) -> 0 3.46/1.61 a__length(cons(X, Y)) -> s(a__length1(Y)) 3.46/1.61 a__length1(X) -> a__length(X) 3.46/1.61 mark(from(X)) -> a__from(mark(X)) 3.46/1.61 mark(length(X)) -> a__length(X) 3.46/1.61 mark(length1(X)) -> a__length1(X) 3.46/1.61 mark(cons(X1, X2)) -> cons(mark(X1), X2) 3.46/1.61 mark(s(X)) -> s(mark(X)) 3.46/1.61 mark(nil) -> nil 3.46/1.61 mark(0) -> 0 3.46/1.61 a__from(X) -> from(X) 3.46/1.61 a__length(X) -> length(X) 3.46/1.61 a__length1(X) -> length1(X) 3.46/1.61 3.46/1.61 S is empty. 3.46/1.61 Rewrite Strategy: FULL 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 3.46/1.61 Transformed a relative TRS into a decreasing-loop problem. 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (2) 3.46/1.61 Obligation: 3.46/1.61 Analyzing the following TRS for decreasing loops: 3.46/1.61 3.46/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). 3.46/1.61 3.46/1.61 3.46/1.61 The TRS R consists of the following rules: 3.46/1.61 3.46/1.61 a__from(X) -> cons(mark(X), from(s(X))) 3.46/1.61 a__length(nil) -> 0 3.46/1.61 a__length(cons(X, Y)) -> s(a__length1(Y)) 3.46/1.61 a__length1(X) -> a__length(X) 3.46/1.61 mark(from(X)) -> a__from(mark(X)) 3.46/1.61 mark(length(X)) -> a__length(X) 3.46/1.61 mark(length1(X)) -> a__length1(X) 3.46/1.61 mark(cons(X1, X2)) -> cons(mark(X1), X2) 3.46/1.61 mark(s(X)) -> s(mark(X)) 3.46/1.61 mark(nil) -> nil 3.46/1.61 mark(0) -> 0 3.46/1.61 a__from(X) -> from(X) 3.46/1.61 a__length(X) -> length(X) 3.46/1.61 a__length1(X) -> length1(X) 3.46/1.61 3.46/1.61 S is empty. 3.46/1.61 Rewrite Strategy: FULL 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (3) DecreasingLoopProof (LOWER BOUND(ID)) 3.46/1.61 The following loop(s) give(s) rise to the lower bound Omega(n^1): 3.46/1.61 3.46/1.61 The rewrite sequence 3.46/1.61 3.46/1.61 mark(from(X)) ->^+ a__from(mark(X)) 3.46/1.61 3.46/1.61 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 3.46/1.61 3.46/1.61 The pumping substitution is [X / from(X)]. 3.46/1.61 3.46/1.61 The result substitution is [ ]. 3.46/1.61 3.46/1.61 3.46/1.61 3.46/1.61 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (4) 3.46/1.61 Complex Obligation (BEST) 3.46/1.61 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (5) 3.46/1.61 Obligation: 3.46/1.61 Proved the lower bound n^1 for the following obligation: 3.46/1.61 3.46/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). 3.46/1.61 3.46/1.61 3.46/1.61 The TRS R consists of the following rules: 3.46/1.61 3.46/1.61 a__from(X) -> cons(mark(X), from(s(X))) 3.46/1.61 a__length(nil) -> 0 3.46/1.61 a__length(cons(X, Y)) -> s(a__length1(Y)) 3.46/1.61 a__length1(X) -> a__length(X) 3.46/1.61 mark(from(X)) -> a__from(mark(X)) 3.46/1.61 mark(length(X)) -> a__length(X) 3.46/1.61 mark(length1(X)) -> a__length1(X) 3.46/1.61 mark(cons(X1, X2)) -> cons(mark(X1), X2) 3.46/1.61 mark(s(X)) -> s(mark(X)) 3.46/1.61 mark(nil) -> nil 3.46/1.61 mark(0) -> 0 3.46/1.61 a__from(X) -> from(X) 3.46/1.61 a__length(X) -> length(X) 3.46/1.61 a__length1(X) -> length1(X) 3.46/1.61 3.46/1.61 S is empty. 3.46/1.61 Rewrite Strategy: FULL 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (6) LowerBoundPropagationProof (FINISHED) 3.46/1.61 Propagated lower bound. 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (7) 3.46/1.61 BOUNDS(n^1, INF) 3.46/1.61 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (8) 3.46/1.61 Obligation: 3.46/1.61 Analyzing the following TRS for decreasing loops: 3.46/1.61 3.46/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(EXP, INF). 3.46/1.61 3.46/1.61 3.46/1.61 The TRS R consists of the following rules: 3.46/1.61 3.46/1.61 a__from(X) -> cons(mark(X), from(s(X))) 3.46/1.61 a__length(nil) -> 0 3.46/1.61 a__length(cons(X, Y)) -> s(a__length1(Y)) 3.46/1.61 a__length1(X) -> a__length(X) 3.46/1.61 mark(from(X)) -> a__from(mark(X)) 3.46/1.61 mark(length(X)) -> a__length(X) 3.46/1.61 mark(length1(X)) -> a__length1(X) 3.46/1.61 mark(cons(X1, X2)) -> cons(mark(X1), X2) 3.46/1.61 mark(s(X)) -> s(mark(X)) 3.46/1.61 mark(nil) -> nil 3.46/1.61 mark(0) -> 0 3.46/1.61 a__from(X) -> from(X) 3.46/1.61 a__length(X) -> length(X) 3.46/1.61 a__length1(X) -> length1(X) 3.46/1.61 3.46/1.61 S is empty. 3.46/1.61 Rewrite Strategy: FULL 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (9) DecreasingLoopProof (FINISHED) 3.46/1.61 The following loop(s) give(s) rise to the lower bound EXP: 3.46/1.61 3.46/1.61 The rewrite sequence 3.46/1.61 3.46/1.61 mark(from(X)) ->^+ cons(mark(mark(X)), from(s(mark(X)))) 3.46/1.61 3.46/1.61 gives rise to a decreasing loop by considering the right hand sides subterm at position [0,0]. 3.46/1.61 3.46/1.61 The pumping substitution is [X / from(X)]. 3.46/1.61 3.46/1.61 The result substitution is [ ]. 3.46/1.61 3.46/1.61 3.46/1.61 3.46/1.61 The rewrite sequence 3.46/1.61 3.46/1.61 mark(from(X)) ->^+ cons(mark(mark(X)), from(s(mark(X)))) 3.46/1.61 3.46/1.61 gives rise to a decreasing loop by considering the right hand sides subterm at position [1,0,0]. 3.46/1.61 3.46/1.61 The pumping substitution is [X / from(X)]. 3.46/1.61 3.46/1.61 The result substitution is [ ]. 3.46/1.61 3.46/1.61 3.46/1.61 3.46/1.61 3.46/1.61 ---------------------------------------- 3.46/1.61 3.46/1.61 (10) 3.46/1.61 BOUNDS(EXP, INF) 3.53/1.64 EOF