4.39/1.89 WORST_CASE(NON_POLY, ?) 4.47/1.90 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 4.47/1.90 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 4.47/1.90 4.47/1.90 4.47/1.90 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.47/1.90 4.47/1.90 (0) CpxTRS 4.47/1.90 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 4.47/1.90 (2) TRS for Loop Detection 4.47/1.90 (3) DecreasingLoopProof [LOWER BOUND(ID), 85 ms] 4.47/1.90 (4) BEST 4.47/1.90 (5) proven lower bound 4.47/1.90 (6) LowerBoundPropagationProof [FINISHED, 0 ms] 4.47/1.90 (7) BOUNDS(n^1, INF) 4.47/1.90 (8) TRS for Loop Detection 4.47/1.90 (9) InfiniteLowerBoundProof [FINISHED, 0 ms] 4.47/1.90 (10) BOUNDS(INF, INF) 4.47/1.90 4.47/1.90 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (0) 4.47/1.90 Obligation: 4.47/1.90 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.47/1.90 4.47/1.90 4.47/1.90 The TRS R consists of the following rules: 4.47/1.90 4.47/1.90 zeros -> cons(0, n__zeros) 4.47/1.90 U11(tt, L) -> U12(tt, activate(L)) 4.47/1.90 U12(tt, L) -> s(length(activate(L))) 4.47/1.90 length(nil) -> 0 4.47/1.90 length(cons(N, L)) -> U11(tt, activate(L)) 4.47/1.90 zeros -> n__zeros 4.47/1.90 activate(n__zeros) -> zeros 4.47/1.90 activate(X) -> X 4.47/1.90 4.47/1.90 S is empty. 4.47/1.90 Rewrite Strategy: FULL 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 4.47/1.90 Transformed a relative TRS into a decreasing-loop problem. 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (2) 4.47/1.90 Obligation: 4.47/1.90 Analyzing the following TRS for decreasing loops: 4.47/1.90 4.47/1.90 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.47/1.90 4.47/1.90 4.47/1.90 The TRS R consists of the following rules: 4.47/1.90 4.47/1.90 zeros -> cons(0, n__zeros) 4.47/1.90 U11(tt, L) -> U12(tt, activate(L)) 4.47/1.90 U12(tt, L) -> s(length(activate(L))) 4.47/1.90 length(nil) -> 0 4.47/1.90 length(cons(N, L)) -> U11(tt, activate(L)) 4.47/1.90 zeros -> n__zeros 4.47/1.90 activate(n__zeros) -> zeros 4.47/1.90 activate(X) -> X 4.47/1.90 4.47/1.90 S is empty. 4.47/1.90 Rewrite Strategy: FULL 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (3) DecreasingLoopProof (LOWER BOUND(ID)) 4.47/1.90 The following loop(s) give(s) rise to the lower bound Omega(n^1): 4.47/1.90 4.47/1.90 The rewrite sequence 4.47/1.90 4.47/1.90 length(cons(N, L)) ->^+ s(length(L)) 4.47/1.90 4.47/1.90 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 4.47/1.90 4.47/1.90 The pumping substitution is [L / cons(N, L)]. 4.47/1.90 4.47/1.90 The result substitution is [ ]. 4.47/1.90 4.47/1.90 4.47/1.90 4.47/1.90 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (4) 4.47/1.90 Complex Obligation (BEST) 4.47/1.90 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (5) 4.47/1.90 Obligation: 4.47/1.90 Proved the lower bound n^1 for the following obligation: 4.47/1.90 4.47/1.90 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.47/1.90 4.47/1.90 4.47/1.90 The TRS R consists of the following rules: 4.47/1.90 4.47/1.90 zeros -> cons(0, n__zeros) 4.47/1.90 U11(tt, L) -> U12(tt, activate(L)) 4.47/1.90 U12(tt, L) -> s(length(activate(L))) 4.47/1.90 length(nil) -> 0 4.47/1.90 length(cons(N, L)) -> U11(tt, activate(L)) 4.47/1.90 zeros -> n__zeros 4.47/1.90 activate(n__zeros) -> zeros 4.47/1.90 activate(X) -> X 4.47/1.90 4.47/1.90 S is empty. 4.47/1.90 Rewrite Strategy: FULL 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (6) LowerBoundPropagationProof (FINISHED) 4.47/1.90 Propagated lower bound. 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (7) 4.47/1.90 BOUNDS(n^1, INF) 4.47/1.90 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (8) 4.47/1.90 Obligation: 4.47/1.90 Analyzing the following TRS for decreasing loops: 4.47/1.90 4.47/1.90 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 4.47/1.90 4.47/1.90 4.47/1.90 The TRS R consists of the following rules: 4.47/1.90 4.47/1.90 zeros -> cons(0, n__zeros) 4.47/1.90 U11(tt, L) -> U12(tt, activate(L)) 4.47/1.90 U12(tt, L) -> s(length(activate(L))) 4.47/1.90 length(nil) -> 0 4.47/1.90 length(cons(N, L)) -> U11(tt, activate(L)) 4.47/1.90 zeros -> n__zeros 4.47/1.90 activate(n__zeros) -> zeros 4.47/1.90 activate(X) -> X 4.47/1.90 4.47/1.90 S is empty. 4.47/1.90 Rewrite Strategy: FULL 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (9) InfiniteLowerBoundProof (FINISHED) 4.47/1.90 The following loop proves infinite runtime complexity: 4.47/1.90 4.47/1.90 The rewrite sequence 4.47/1.90 4.47/1.90 length(cons(N, n__zeros)) ->^+ s(length(cons(0, n__zeros))) 4.47/1.90 4.47/1.90 gives rise to a decreasing loop by considering the right hand sides subterm at position [0]. 4.47/1.90 4.47/1.90 The pumping substitution is [ ]. 4.47/1.90 4.47/1.90 The result substitution is [N / 0]. 4.47/1.90 4.47/1.90 4.47/1.90 4.47/1.90 4.47/1.90 ---------------------------------------- 4.47/1.90 4.47/1.90 (10) 4.47/1.90 BOUNDS(INF, INF) 4.51/1.93 EOF