3.12/1.61 WORST_CASE(NON_POLY, ?) 3.12/1.61 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 3.12/1.61 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 3.12/1.61 3.12/1.61 3.12/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.12/1.61 3.12/1.61 (0) CpxTRS 3.12/1.61 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 3.12/1.61 (2) TRS for Loop Detection 3.12/1.61 (3) InfiniteLowerBoundProof [FINISHED, 0 ms] 3.12/1.61 (4) BOUNDS(INF, INF) 3.12/1.61 3.12/1.61 3.12/1.61 ---------------------------------------- 3.12/1.61 3.12/1.61 (0) 3.12/1.61 Obligation: 3.12/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.12/1.61 3.12/1.61 3.12/1.61 The TRS R consists of the following rules: 3.12/1.61 3.12/1.61 f(X) -> f(X) 3.12/1.61 c -> a 3.12/1.61 c -> b 3.12/1.61 3.12/1.61 S is empty. 3.12/1.61 Rewrite Strategy: FULL 3.12/1.61 ---------------------------------------- 3.12/1.61 3.12/1.61 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 3.12/1.61 Transformed a relative TRS into a decreasing-loop problem. 3.12/1.61 ---------------------------------------- 3.12/1.61 3.12/1.61 (2) 3.12/1.61 Obligation: 3.12/1.61 Analyzing the following TRS for decreasing loops: 3.12/1.61 3.12/1.61 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 3.12/1.61 3.12/1.61 3.12/1.61 The TRS R consists of the following rules: 3.12/1.61 3.12/1.61 f(X) -> f(X) 3.12/1.61 c -> a 3.12/1.61 c -> b 3.12/1.61 3.12/1.61 S is empty. 3.12/1.61 Rewrite Strategy: FULL 3.12/1.61 ---------------------------------------- 3.12/1.61 3.12/1.61 (3) InfiniteLowerBoundProof (FINISHED) 3.12/1.61 The following loop proves infinite runtime complexity: 3.12/1.61 3.12/1.61 The rewrite sequence 3.12/1.61 3.12/1.61 f(X) ->^+ f(X) 3.12/1.61 3.12/1.61 gives rise to a decreasing loop by considering the right hand sides subterm at position []. 3.12/1.61 3.12/1.61 The pumping substitution is [ ]. 3.12/1.61 3.12/1.61 The result substitution is [ ]. 3.12/1.61 3.12/1.61 3.12/1.61 3.12/1.61 3.12/1.61 ---------------------------------------- 3.12/1.61 3.12/1.61 (4) 3.12/1.61 BOUNDS(INF, INF) 3.12/1.64 EOF