2.89/1.57 WORST_CASE(NON_POLY, ?) 2.89/1.58 proof of /export/starexec/sandbox/benchmark/theBenchmark.xml 2.89/1.58 # AProVE Commit ID: 48fb2092695e11cc9f56e44b17a92a5f88ffb256 marcel 20180622 unpublished dirty 2.89/1.58 2.89/1.58 2.89/1.58 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.89/1.58 2.89/1.58 (0) CpxTRS 2.89/1.58 (1) RelTrsToDecreasingLoopProblemProof [LOWER BOUND(ID), 0 ms] 2.89/1.58 (2) TRS for Loop Detection 2.89/1.58 (3) InfiniteLowerBoundProof [FINISHED, 0 ms] 2.89/1.58 (4) BOUNDS(INF, INF) 2.89/1.58 2.89/1.58 2.89/1.58 ---------------------------------------- 2.89/1.58 2.89/1.58 (0) 2.89/1.58 Obligation: 2.89/1.58 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.89/1.58 2.89/1.58 2.89/1.58 The TRS R consists of the following rules: 2.89/1.58 2.89/1.58 f(g(X), Y) -> f(X, f(g(X), Y)) 2.89/1.58 2.89/1.58 S is empty. 2.89/1.58 Rewrite Strategy: FULL 2.89/1.58 ---------------------------------------- 2.89/1.58 2.89/1.58 (1) RelTrsToDecreasingLoopProblemProof (LOWER BOUND(ID)) 2.89/1.58 Transformed a relative TRS into a decreasing-loop problem. 2.89/1.58 ---------------------------------------- 2.89/1.58 2.89/1.58 (2) 2.89/1.58 Obligation: 2.89/1.58 Analyzing the following TRS for decreasing loops: 2.89/1.58 2.89/1.58 The Runtime Complexity (full) of the given CpxTRS could be proven to be BOUNDS(INF, INF). 2.89/1.58 2.89/1.58 2.89/1.58 The TRS R consists of the following rules: 2.89/1.58 2.89/1.58 f(g(X), Y) -> f(X, f(g(X), Y)) 2.89/1.58 2.89/1.58 S is empty. 2.89/1.58 Rewrite Strategy: FULL 2.89/1.58 ---------------------------------------- 2.89/1.58 2.89/1.58 (3) InfiniteLowerBoundProof (FINISHED) 2.89/1.58 The following loop proves infinite runtime complexity: 2.89/1.58 2.89/1.58 The rewrite sequence 2.89/1.58 2.89/1.58 f(g(X), Y) ->^+ f(X, f(g(X), Y)) 2.89/1.58 2.89/1.58 gives rise to a decreasing loop by considering the right hand sides subterm at position [1]. 2.89/1.58 2.89/1.58 The pumping substitution is [ ]. 2.89/1.58 2.89/1.58 The result substitution is [ ]. 2.89/1.58 2.89/1.58 2.89/1.58 2.89/1.58 2.89/1.58 ---------------------------------------- 2.89/1.58 2.89/1.58 (4) 2.89/1.58 BOUNDS(INF, INF) 2.89/1.62 EOF